Can you implode an array into function arguments?

Question

Is it possible to have an array and pass it into a function as separate arguments?

$name = array('test', 'dog', 'cat');
$name = implode(',' $name);
randomThing($name);

function randomThing($args) {
    $args = func_get_args();
    // Would be 'test', 'dog', 'cat'

    print_r($args);
}

Ignacio Vazquez-Abrams · Accepted Answer · 2012-04-22 21:23:32Z

12

No. That's what call_user_func_array() is for.

answered Apr 22, 2012 at 21:23

Ignacio Vazquez-Abrams

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Comments

Beat · Accepted Answer · 2017-12-29 09:45:05Z

9

As of PHP 5.6 you can use ... to pass an array as function arguments. See this example from the PHP documentation:

function add($a, $b) {
    return $a + $b;
}

echo add(...[1, 2])."\n";

$a = [1, 2];
echo add(...$a);

answered Dec 29, 2017 at 9:45

Beat

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1 Comment

jah Over a year ago

"... can also be used when calling functions to unpack an array or Traversable variable or literal into the argument list"

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