Using a for-in loop with NSInteger?

Question

I have an NSMutableArray populated with NSIntegers. I need to loop through the array. I could do:

// given NSMutableArray *array of NSIntegers
NSUInteger n = [array count];
for (NSInteger i = 0; i < n; i++) {
  NSInteger x = [array objectAtIndex:i];
  // query SQLite WHERE id = x
}

However, it seems that a for (object in array) loop would be cleaner. iOS 5 does not accept NSIntegers or NSNumbers as objects in for-in loops. Should I loop through the array with NSObjects, casting the NSObject to an NSInteger during each iteration? Is there another way? Or is a for loop like the one above the cleanest solution to this problem?

Jonathan Naguin · Accepted Answer · 2012-04-24 07:39:12Z

7

In Objective-C you can use a for-in loop with NSNumber like this:

    NSArray *array = /*NSArray with NSNumber*/;

    for (NSNumber *n in array) {
        NSLog(@"i: %d", [n intValue]);
    }

Check this out.

answered Apr 24, 2012 at 7:39

Jonathan Naguin

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1 Comment

tenedor Over a year ago

great thanks. NSNumber still needs to be converted to NSInteger for some operations, but this is nice and clean

M. Adam · Accepted Answer · 2020-05-19 13:06:17Z

0

Mostly, you will not be allowed to have an NSMutableArray of NSUInteger (aka unsigned long) as it's not an objective-c object.

You may use the c style.

NSUInteger array[] = {value1,value2,value3};
int size = sizeof(array)/sizeof(array[0]);
for (int i=0; i<size; i++) {
   NSInteger value = array[i];
   // do whatever you want
}

edited May 19, 2020 at 13:06

answered May 19, 2020 at 12:58

M. Adam

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