161

I have following XML stored in a XML column (called Roles) in a SQL Server database.

<root>
   <role>Alpha</role>
   <role>Beta</role>
   <role>Gamma</role>
</root>

I'd like to list all rows that have a specific role in them. This role passed by parameter.

9 Answers 9

243
select
  Roles
from
  MyTable
where
  Roles.value('(/root/role)[1]', 'varchar(max)') like 'StringToSearchFor'

In case your column is not XML, you need to convert it. You can also use other syntax to query certain attributes of your XML data. Here is an example...

Let's suppose that data column has this:

<Utilities.CodeSystems.CodeSystemCodes iid="107" CodeSystem="2" Code="0001F" CodeTags="-19-"..../>

... and you only want the ones where CodeSystem = 2 then your query will be:

select 
  [data] 
from
  [dbo].[CodeSystemCodes_data]
  
where
  CAST([data] as XML).value('(/Utilities.CodeSystems.CodeSystemCodes/@CodeSystem)[1]', 'varchar(max)') = '2'

These pages will show you more about how to query XML in T-SQL:

Querying XML fields using t-sql

Flattening XML Data in SQL Server

EDIT

After playing with it a little bit more, I ended up with this amazing query that uses CROSS APPLY. This one will search every row (role) for the value you put in your like expression...

Given this table structure:

create table MyTable (Roles XML)

insert into MyTable values
('<root>
   <role>Alpha</role>
   <role>Gamma</role>
   <role>Beta</role>
</root>')

We can query it like this:

select * from 

(select 
       pref.value('(text())[1]', 'varchar(32)') as RoleName
from 
       MyTable CROSS APPLY

       Roles.nodes('/root/role') AS Roles(pref)
)  as Result

where RoleName like '%ga%'

You can check the SQL Fiddle here: http://sqlfiddle.com/#!18/dc4d2/1/0

Sign up to request clarification or add additional context in comments.

7 Comments

It answers all my question, what does [1] do in your answer?
Great answer, I vote for this one, but string should be varchar I guess
@Bistro Asking about [1] was a really good question. It means that you pick the first role value from the XML and that means that this will only work for finding Alpha in your sample xml. It will not find the row if you search for Beta.
In my case, I had to query nodes with specific attribute value. This answer was the lead to my solution. I just had to put double quotes around the attribute value.
Getting - "Cannot call methods on nvarchar(max)". Can anyone please suggest
|
41
declare @T table(Roles xml)

insert into @T values
('<root>
   <role>Alpha</role>
   <role>Beta</role>
   <role>Gamma</role>
</root>')

declare @Role varchar(10)

set @Role = 'Beta'

select Roles
from @T
where Roles.exist('/root/role/text()[. = sql:variable("@Role")]') = 1

If you want the query to work as where col like '%Beta%' you can use contains

declare @T table(Roles xml)

insert into @T values
('<root>
   <role>Alpha</role>
   <role>Beta</role>
   <role>Gamma</role>
</root>')

declare @Role varchar(10)

set @Role = 'et'

select Roles
from @T
where Roles.exist('/root/role/text()[contains(., sql:variable("@Role"))]') = 1

Comments

14

if your field name is Roles and table name is table1 you can use following to search

DECLARE @Role varchar(50);
SELECT * FROM table1
WHERE Roles.exist ('/root/role = sql:variable("@Role")') = 1

3 Comments

this is good, is here any way to search the using like? forexample /root/role like ....
use .value('(/root/role)[1]', 'varchar(max)') like '%yourtext%' instead of exists as Leniel explained
Have you tried this? It finds everything, regardless of what you put in @Role.
12

I came up with a simple work around below which is easy to remember too :-)

select * from  
(select cast (xmlCol as varchar(max)) texty
 from myTable (NOLOCK) 
) a 
where texty like '%MySearchText%'

1 Comment

We're not supposed to search via string manipulation, as that would result in way too slow searches
6

You could do the following

declare @role varchar(100) = 'Alpha'
select * from xmltable where convert(varchar(max),xmlfield) like '%<role>'+@role+'</role>%'

Obviously this is a bit of a hack and I wouldn't recommend it for any formal solutions. However I find this technique very useful when doing adhoc queries on XML columns in SQL Server Management Studio for SQL Server 2012.

Comments

2

Useful tip. Query a value in SQL Server XML column (XML with namespace)

e.g.

Table [dbo].[Log_XML] contains columns Parametrs (xml),TimeEdit (datetime)

e.g. XML in Parametrs:

<ns0:Record xmlns:ns0="http://Integration"> 
<MATERIAL>10</MATERIAL> 
<BATCH>A1</BATCH> 
</ns0:Record>

e.g. Query:

select
 Parametrs,TimeEdit
from
 [dbo].[Log_XML]
where
 Parametrs.value('(//*:Record/BATCH)[1]', 'varchar(max)') like '%A1%'
 ORDER BY TimeEdit DESC

Comments

1

I used the below statement to retrieve the values in the XML in the Sql table

with xmlnamespaces(default 'http://test.com/2008/06/23/HL.OnlineContract.ValueObjects')
select * from (
select
            OnlineContractID,
            DistributorID,
            SponsorID,
    [RequestXML].value(N'/OnlineContractDS[1]/Properties[1]/Name[1]', 'nvarchar(30)') as [Name]
   ,[RequestXML].value(N'/OnlineContractDS[1]/Properties[1]/Value[1]', 'nvarchar(30)') as [Value]
     ,[RequestXML].value(N'/OnlineContractDS[1]/Locale[1]', 'nvarchar(30)') as [Locale]
from [OnlineContract]) as olc
where olc.Name like '%EMAIL%' and olc.Value like '%EMAIL%' and olc.Locale='UK EN'

1 Comment

What if XML does not contain Namespace definition ?
0

You can query the whole tag, or just the specific value. Here I use a wildcard for the xml namespaces.

declare @myDoc xml
set @myDoc = 
'<Root xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://stackoverflow.com">
    <Child>my value</Child>
 </Root>'

select @myDoc.query('/*:Root/*:Child') -- whole tag
select @myDoc.value('(/*:Root/*:Child)[1]', 'varchar(255)') -- only value

Comments

0

In case you want to find other node besides "Alpha", the query should be something like this:

select Roles from MyTable where Roles.exist('(/*:root/*:role[contains(.,"Beta")])') = 1

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.