include a header under a custom namespace?

Question

I'm using a third party C++ lib in one of my current projects. Their lib does not define a custom namespace, though. So, all of their functions are just out there. This isn't a big deal, but ideally they'd have used a namespace.

Is it possible to #include their header files under a custom pseudo namespace of some kind? This way, all of their functions could be included in a namespace.

Are there seperate implementation files, or is the library header-only? — Seth Carnegie
– Seth Carnegie, Commented Apr 28, 2012 at 16:11
The implementation is there as well, but if it means editing their code I think I'd rather just use it as-is without the namespace. — Ryan
– Ryan, Commented Apr 28, 2012 at 16:13
Well since #include is literally copy-paste, you could do namespace something { #include "header" }, however that won't work if there are other files that #include "header" and don't put the namespace something { } around it (like the implementation files). So there's really no way around manually editing all the files. — Seth Carnegie
– Seth Carnegie, Commented Apr 28, 2012 at 16:14

tim-oleksii · Accepted Answer · 2012-04-28 16:31:11Z

1

You cannot do that as long as this will change the name of the function( for C++ ). Linker will append the name of the namespace to the function, so the linkage will be failed due to the absence of the functions.

For instace for the following code

namespace MyName
{
    class MyNestedOne
    {
    public:
        void doNothing( );
    };
};

the function doNothing will have following name doNothing@MyNestedOne@MyName@@

edited Apr 28, 2012 at 16:31

answered Apr 28, 2012 at 16:23

tim-oleksii

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phantasmagoria · Accepted Answer · 2012-04-28 19:06:35Z

0

As you say, if they were in a namespace it would be better. However it is not much of a concern.

Alternatively if you are able to have the .dll instead of .lib, you can bind it dynamically, use it, and let it go. This way you wont have floating functions for the whole run-time.

answered Apr 28, 2012 at 19:06

phantasmagoria

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