jQuery javascript scoping problem

Question

I have a hidden input element that I am using as a counter to use to name more input elements generated by JavaScript. To get the value of the counter i use

parseInt($('#counter').val());

However I use this code snippet several times in my code, so I thought it would be good to put it in a function

function getCounter(){
   parseInt($('#counter').val());
}

this always returns undefined, while running just the code snippet returns the correct value. This happens in several ways that I tried defeining the function, as a function inside a $(function(){}), as a global function etc. How do I fix the scoping?

James Skidmore · Accepted Answer · 2009-06-24 15:39:25Z

6

Add "return" to your return statement :)

function getCounter(){
   return parseInt($('#counter').val());
}

answered Jun 24, 2009 at 15:39

James Skidmore

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4 Comments

James Skidmore Over a year ago

Don't feel silly... it's always the little, assumed things that are impossible to catch. It just usually takes a fresh pair of eyes :)

epascarello Over a year ago

Only thing that is wrong with the solution is it needs to have the base included. return parseInt($('#counter').val(), 10); so you do not run into the Octal problem.

Jonathan Rupp Over a year ago

Yeah, I missed the missing return too. I was just getting ready to add a comment asking for more code, thinking it was really a scoping problem....

w00t Over a year ago

@Craig, you may want to look into CoffeeScript... It's Javascript for Ruby escapees :)

jitter · Accepted Answer · 2009-06-24 15:40:10Z

2

How about adding a return

function getCounter(){
   return parseInt($('#counter').val());
}

answered Jun 24, 2009 at 15:40

jitter

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