How to access value from array returned from a function without declaring a temporary variable?

Question

I was wondering if there is a way to return an array value from a function that returns an array inline. So if I have a function like:

class MyObj
{
    public function myFunction()
    {
         return array('arrayIndex'=>'myValue');
    }
}

I would like to be able to do this:

$object = new MyObj();
$myValue = $object->myFunction()['arrayIndex']; //but this doesn't work

rather than this:

 $object = new MyObj();
 $myArray = $object->myFunction();
 $myValue = $myArray['arrayIndex'];

Simple question but I just don't know if its possible to reference it in a similar way. So yay or nay?

Please do your homework before posting a question. You find it in the manual here: php.net/manual/en/language.types.array.php#example-87 — hakre
– hakre, Commented May 1, 2012 at 15:28

John Conde · Accepted Answer · 2012-05-01 14:50:56Z

5

Upgrade to PHP 5.4 and you can then do array dereferencing.

answered May 1, 2012 at 14:50

John Conde

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Comments

fhugas · Accepted Answer · 2012-05-01 14:52:31Z

0

What about

class MyObj
{
    public function myFunction($index)
    {
        $your_array = array('arrayIndex'=>'myValue');
        return $your_array[$index];
    }
}


f$object = new MyObj();
$myValue = $object->myFunction('arrayUndex');

answered May 1, 2012 at 14:52

fhugas

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1 Comment

mickmackusa Over a year ago

what the f ??

gspd · Accepted Answer · 2012-05-01 15:44:23Z

0

class MyObj
{
    public function myFunction()
    {
         return array($one,$two);
    }
}


f$object = new MyObj();
list($first,$second) = $object->myFunction();

answered May 1, 2012 at 15:44

gspd

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1 Comment

mickmackusa Over a year ago

What the f ??

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