Parse JSON without a particular standard structure into a Map or Java Object

Question

It will be great if I can map the json to a Java object but the structure is pretty weird, it is different for all the json I am trying to parse. eg categories and topics can have different. How I can map it to a Java object, or any other suggestion??

"name":"url", "categories": { "249":{"catID":"249","score":33.43533451973102}, "34":{"catID":"34","score":3.0000000447034836}, .,.,so on }, "topics":{ "DSLR":{"weight":1.6690950917579026,"noun":1}, "illuminated":{"weight":7.6470197510265105,"noun":0}, . .so on }}

Take a look at this: How to convert arbitrary JSON into a usable structure in Java — Greg Kopff
– Greg Kopff, Commented May 1, 2012 at 23:44
Here is the output from GSON library: topics/{DSLR={weight=1.6690950917579026, noun=1}, illuminated={weight=7.6470197510265105, noun=0}, } How can I now represent it in a JAVA object, considering multiple categories and topics source/high categories/{2_249={categoryID=249, taxID=2, score=33.43533451973102},...} — gaurav kumar
– gaurav kumar, Commented May 1, 2012 at 23:48

rmberg · Accepted Answer · 2012-05-01 23:18:41Z

1

Can you at least count on the JSON representation being consistent for each type of response / object mapping? If so, you can use the Google GSON library, and create a custom deserializer to handle the non-standard JSON representation. Here is a link to the project:

http://code.google.com/p/google-gson/

and to the user guide on how to create custom serializers / deserializers:

https://sites.google.com/site/gson/gson-user-guide#TOC-Custom-Serialization-and-Deserialization

answered May 1, 2012 at 23:18

rmberg

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gaurav kumar Over a year ago

I tried your suggestion and implemented a GSON way to parse the JSON this is the output topics/{DSLR={weight=1.6690950917579026, noun=1}, illuminated={weight=7.6470197510265105, noun=0}, } source/high categories/{2_249={categoryID=249, taxID=2, score=33.43533451973102},...} How can I now represent this in a JAVA object?

Yusuf X · Accepted Answer · 2012-05-01 23:14:11Z

0

There is a library for that: org.json . To parse a JSONObject from a String, you say:

JSONObject jo = new JSONObject(string);

However, if the string represents an array instead of a map, use:

JSONArray ja = new JSONArray(string);

answered May 1, 2012 at 23:14

Yusuf X

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