Php code for is not in array

Question

I need a little bit of help, being a newb with php.

if($catname != 'used-cars' && $currentpage IS NOT 1,2,3.....100){
}

How can I write this corectly? Maybe put the numbers inside an array?

Ty

So $currentpage will be a single number?

Felix Kling
– Felix Kling

2012-05-02 16:08:53 +00:00
Commented May 2, 2012 at 16:08 — Felix Kling
– Felix Kling, Commented May 2, 2012 at 16:08
Looks like $currentpage is a page id.

Jeff Hines
– Jeff Hines

2012-05-02 16:10:30 +00:00
Commented May 2, 2012 at 16:10 — Jeff Hines
– Jeff Hines, Commented May 2, 2012 at 16:10

Pheonix · Accepted Answer · 2012-05-02 16:05:02Z

2

Use ! and in_array()

$array = array(1, 2, 3... , 100);

if($catname != 'used-cars' && !in_array($currentpage, $array)){

}

http://php.net/manual/en/function.in-array.php

answered May 2, 2012 at 16:05

Pheonix

6,0627 gold badges32 silver badges48 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

user142162 · Accepted Answer · 2012-05-02 16:04:25Z

1

if($catname != 'used-cars' && !in_array($currentpage, range(1, 100))

Or:

if($catname != 'used-cars' && ($currentpage < 1 || $currentpage > 100))

answered May 2, 2012 at 16:04

user142162

1 Comment

Logan Serman Over a year ago

This is a nice solution if 1, 2, 3, ... 100 was actually what he was going for... I just assumed that the data was not always necessarily a range.

Logan Serman · Accepted Answer · 2012-05-02 16:03:41Z

0

if($catname != 'used-cars' && !in_array($currentPage, array(1, 2, 3, ..., 100)))
{}

answered May 2, 2012 at 16:03

Logan Serman

30k28 gold badges107 silver badges144 bronze badges

Comments

Madara's Ghost · Accepted Answer · 2012-05-02 16:05:25Z

0

Assuming you want all numbers withing the range of 1-100, you can use in_array() and range() like so:

if (($catname != "used-cars") && (!in_array($currentPage, range(1,100))) {
   //Do Stuff
}

answered May 2, 2012 at 16:05

Madara's Ghost

176k52 gold badges274 silver badges314 bronze badges

Comments

Jeff Hines · Accepted Answer · 2012-05-02 16:07:01Z

0

Maybe something like this might work?

if($catname != 'used-cars' && $currentpage > 100)
{
    //Code here
}

answered May 2, 2012 at 16:07

Jeff Hines

3,5211 gold badge21 silver badges21 bronze badges

Collectives™ on Stack Overflow

Php code for is not in array

5 Answers 5

Comments

1 Comment

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

Comments

1 Comment

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related