php + javascript string checking

Question

I have a string that is failing to pass the below requirement:-

$uid = ca11a15e (the value called from database)

function _checkSn($uid)    
{
   $match1 = preg_match('/^p[a-z\d][a-z\d][1-6][a-z]\d{2}e$/',$uid);
   $match2 = preg_match('/^p[a-z\d][a-z\d]school$/',$uid);
   $match3 = preg_match('/^p[a-z\d][a-z\d]master$/',$uid);
   $match4 = preg_match('/^p[a-z\d][a-z\d]ee01$/',$uid);
   $doesMatch = ($match1 || $match2 || $match3 || $match4);
   return $doesMatch; 
}

Actually, what is the phase talking about? and how shall I modify it so that the $uid can pass the checking?

should $uid's value be inside quotes? Is that a typo or how your program is? — LeonardChallis
– LeonardChallis, Commented May 3, 2012 at 7:09
the $uid is generated by the system, with the following rule cal = school 1a = class of the student 15 = class number of the student e = course enrolled — Ham
– Ham, Commented May 3, 2012 at 7:12
should $uid = ca11a15e be $uid = 'ca11a15e' is basically @LeonardChallis question — Andreas Wong
– Andreas Wong, Commented May 3, 2012 at 7:12
Also you can combine your 4 RegEx'es to one like preg_match('/^p[a-z\d][a-z\d]([1-6][a-z]\d{2}e|school|master|ee01)$/',$uid); — s.webbandit
– s.webbandit, Commented May 3, 2012 at 7:13

psx · Accepted Answer · 2012-05-03 07:55:32Z

Short answer

Your uid does not begin with a 'p'. All rules are checking that it begins with 'p'.

Long answer

$match1 = preg_match('/^p[a-z\d][a-z\d][1-6][a-z]\d{2}e$/',$uid);

This is checking for something of the format: the letter p, lowercase letter, 1 digit number, lowercase letter, 1 digit number, number from 1 to 6, lowercase letter, number (1 or 2 digits), the letter e

$match2 = preg_match('/^p[a-z\d][a-z\d]school$/',$uid);

This is checking for something of the format: the letter p, lowercase letter, 1 digit number, lowercase letter, 1 digit number, the word 'school'

$match3 = preg_match('/^p[a-z\d][a-z\d]master$/',$uid);

This is checking for something of the format: the letter p, lowercase letter, 1 digit number, lowercase letter, 1 digit number, the word 'master'

$match4 = preg_match('/^p[a-z\d][a-z\d]ee01$/',$uid);

This is checking for something of the format: the letter p, lowercase letter, 1 digit number, lowercase letter, 1 digit number, the string 'ee01'

EDIT

If you wish to add 'c' to the allowed characters at the start of the matching, you can, for example do:

$match1 = preg_match('/^[cp][a-z\d][a-z\d][1-6][a-z]\d{2}e$/',$uid);

[cp] instead of p checks for EITHER c or p as the first letter.

Armatus · Accepted Answer · 2012-05-03 07:20:20Z

0

return (preg_match('/^p[a-z\d][a-z\d][1-6][a-z]\d{2}e$/',$uid) 
|| preg_match('/^p[a-z\d][a-z\d]school$/',$uid) 
|| preg_match('/^p[a-z\d][a-z\d]master$/',$uid) 
|| preg_match('/^p[a-z\d][a-z\d]ee01$/',$uid));

uid matches the pattern if it is...

"p", two times either a lowercase letter or digit, followed by
one digit 1-6, another letter, two digits, "e" or "school" or "master" or "ee01"

For example, this would match: "p6t3h56e" (first pattern), or "p9hschool" (second).

"ca11a15e" will not match any of these because they all require a "p" at the start.

By the way, this can be shortened to:

return (preg_match('/^p[a-z\d]{2}([1-6][a-z]\d{2}e|school|master|ee01)$/',$uid);

Are all the uid's going to start with a c? Maybe you meant this, which would match "ca11a15e" (Note the c instead of p):

return (preg_match('/^c[a-z\d]{2}([1-6][a-z]\d{2}e|school|master|ee01)$/',$uid);

answered May 3, 2012 at 7:20

Armatus

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2 Comments

Ham Over a year ago

may I change it to (preg_match('/^[a-z\d]{2}([1-6][a-z]\d{2}e|school|master|ee01)$/',$uid) so that the first 2 characters can be any letter? or I shall I change it to (preg_match('/^pc[a-z\d]{2}([1-6][a-z]\d{2}e|school|master|ee01)$/',$uid) so that it can cater both c and p?

Armatus Over a year ago

To allow for either p or c, you need to put them in a group like [cp]. Just cp would only match if there were both c and p.

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