The following code generates random number from 1 to 10
$ran = rand(1,10);
What if i want random numbers from my custom values.that is (1,3,6,7,9)
for example i need to generate any one number from the group (1,3,6,7,9)
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3 Answers
You can do that as following,
<?PHP
$numbers = array(1 => 1, 2 => 2, 3 => 3, 4 => 4, 5 => 5, 6 => 6);
$random_key = array_rand($numbers, 1);
print $random_key;
?>
3 Comments
Madara's Ghost
The keys here are reluctant. using
$numbers[array_rand($numbers)] is enough.
Pankajj Kumar
WAIT..i want this value (1,3,6,7,9) ,,,1 => 5, 2 => 9, 3 => 6, 4 => 9, 5 => 11, 6 => 4); when i do like that i get 1,2,3,4,5, only
Madara's Ghost
@PankajjKumar: It's the keys which matter in this example.
You want array_rand()
or you could shuffle() and always just reference $array[0] which would also be "random"
2 Comments
Madara's Ghost
You should try and provide an example
Blake
I'd rather have anyone searching or the OP to learn to utilize the PHP manual than just get specific examples on SO. Understanding the direct source with examples is more important than providing a specific example to the OP's case, in my opinion.
You need array_rand function for that . the Parameters are array_rand ( array $input [, int $num_req = 1 ] ) . For your purpose , use it as $var_rand = array_rand($arr); as you want only 1 random number generated . For more help, refer to this
Also , for future questions , post your php version too. Some functions are not available in older versions . This one is available , though.
