PHP: Array passed by reference to a function?

Question

I have this php function that has to perform some processing on a given array:

processArray($arrayToProcess) {

  $arrayToProcess['helloStackOverflow'] = TRUE;
}

Later, the code invokes the following:

$niceArray = array('key' => 'value');
processArray($niceArray);

The key 'helloStackOverflow' isn't available outside the processArray function. I tried calling the following:

processArray(&$niceArray);

Using "&" helps, however it raises some warning:

Deprecated function: Call-time pass-by-reference has been deprecated; If you would like to pass it by reference, modify the declaration of populateForm_withTextfields()

Tried the & in there, but that just stops the code.

How should I do this?

xCander · Accepted Answer · 2012-05-07 13:39:44Z

18

You have to define the reference in the function, not in the call to the function.

function processArray(&$arrayToProcess) {

answered May 7, 2012 at 13:39

xCander

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Community · Accepted Answer · 2023-11-17 19:41:46Z

8

processArray(&$arrayToProcess) {

  $arrayToProcess['helloStackOverflow'] = TRUE;
}

implements the reference in PHP way.

See https://www.php.net/references for useful information about references.

edited Nov 17, 2023 at 19:41

CommunityBot

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answered May 7, 2012 at 13:39

Smar

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Comments

dm03514 · Accepted Answer · 2012-05-07 13:38:55Z

5

processArray(&$arrayToProcess) {

  $arrayToProcess['helloStackOverflow'] = TRUE;
}

Referencing passing now takes place at the function declaration, not when the function is called.

http://php.net/manual/en/language.references.pass.php

for full documentation.

answered May 7, 2012 at 13:38

dm03514

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