How can i get String Variables from a given String

Question

how to get string variables from a whole string in java.

if i am given a string which is created this way:

String s = "Name:" + name + "Age:" + age + "Sex:" + sex;

how can i get name, age, sex from this String s.

I cannot use getWord(position) or something like that because i dont know how many words will be there in name, and how the age is represented age = "22 years" or age = "22 years 5 months".

If you don't have separators between your fields, this will be messy... — Denys Séguret
– Denys Séguret, Commented May 9, 2012 at 7:55
Your string concatenation doesn't have spaces, so, for example, I would come up as "Name:GregAge:32Sex:male" — Greg Kopff
– Greg Kopff, Commented May 9, 2012 at 7:57
No need to use regex. Simply getIndex('Age:') will get the end of the first value. — Denys Séguret
– Denys Séguret, Commented May 9, 2012 at 7:57
@ greg in my actual code i use spaces...but just to show to clearly i didnt show it here..sry — Housefly
– Housefly, Commented May 9, 2012 at 7:58

score 2 · Accepted Answer · 2012-05-09 08:28:14Z

2

I suggest you to have the Name, Age and Sex splitted by "," character.

It means:

String s = "Name:" + name + ",Age:" + age + ",Sex:" + sex;

Then you can split the string s by ","

String properties = s.split(",");

Then from properties variable, you can split by ":" to take the Property name and the value of that property.

Is that clear?

I'm adding more code to support another ways as you wanted:

String name = "Thuan";
String age = "27";
String sex = "male";
String s = "Name:" + name + "Age:" + age + "Sex:" + sex;

int nameIndex = s.indexOf("Name:");
int ageIndex = s.indexOf("Age:");
int sexIndex = s.indexOf("Sex:");

String theName = s.substring(nameIndex + "Name:".length(), ageIndex);
String theAge = s.substring(ageIndex + "Age:".length(), sexIndex);
String theSex = s.substring(sexIndex + "Sex:".length(), s.length());

System.out.println(theName);
System.out.println(theAge);
System.out.println(theSex);

Please be note that this is just example show you the logic, you need to refactor yourself.

edited May 9, 2012 at 8:28

answered May 9, 2012 at 7:59

user1373996

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4 Comments

Housefly Over a year ago

clear..thankyou... but is there a way i can achieve this without using delimiters...because i need to show the whole string as well...it wont look good with delimiters.

user1373996 Over a year ago

Yes. there is. Just define your property names as constants. Try to use them with s.startWiths and s.indexOf :) I guess it will works. But need to use the logic well.

user1373996 Over a year ago

For example: use s.indexOf("Name:") and you have the index of Name:, do the same with Age: and Sex:. You will have 3 indexes numbers, right? Then you sort them ascending. Now you can get it by index[0] -> index[1] => property 1, index[1] -> index[2] => property 2... so on...

user1373996 Over a year ago

And also please note that you should refactor the code yourself, my code is just example. For example: Name: and Age: and Sex: should be defined as Constants.

phantasmagoria · Accepted Answer · 2012-05-09 07:58:06Z

1

You will go on reading the name (after the "NAME:" ofcourse) until you are encountered with four subsequent letters "AGE:" and then go on reading the age until you are encountered with four subsequent letters "SEX:" and the rest is the sex data.

Edit: Actually " : " may be your seperator if it is not included in data.

answered May 9, 2012 at 7:58

phantasmagoria

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2 Comments

maress Over a year ago

According to the question, this might possibly be the correct way to do it, unless the variables have specific delimiting characters. And we assume that the words 'age' and 'sex' are not allowed to appear anywhere in the variable values.

phantasmagoria Over a year ago

@maress Yes, as I edited the post: If " : " is not included in the data for sure, it is easier to divide the string by the delimiting character " : ".

Carmelo Foti · Accepted Answer · 2012-05-09 07:58:34Z

0

If you have a delimiting character you can use the String.split() method. For example, have

s = "Name: carmelo; Age: 25 years; Sex: m;"

then you can call

String[] values = s.split(";")
String name = values[0].split(":")[1];
String age = values[1].split(":")[1];
String sex = values[2].split(":")[1];

answered May 9, 2012 at 7:58

Carmelo Foti

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1 Comment

Housefly Over a year ago

but is there a way i can achieve this without using delimiters...because i need to show the whole string as well...it wont look good with delimiters.

avani gadhai · Accepted Answer · 2012-05-09 07:59:49Z

0

Make use of "Split"

String s = "Name:" + name + "#Age:" + age + "#Sex:" + sex;
String[] splits = s.split("#");

System.out.println("splits.size: " + splits.length);

for(int i=0; i < splits.length; i++){
//System.out.println(splits[i] );
String[] values= splits[i].split(":");

System.out.println(values[0]+" = " + values[1] );
}

answered May 9, 2012 at 7:59

avani gadhai

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Comments

Edwin Bautista · Accepted Answer · 2012-05-09 08:03:54Z

0

There should be proper delimiters on the created String s, otherwise it would be impossible to split them into arrays of strings.

For example:

private static final String FIELD_DELIMITER = ";";
private static final String DATA_DELIMITER = "=";

String s = "Name" + DATA_DELIMITER + name + FIELD_DELIMITER +
           "Age" + DATA_DELIMITER + age + FIELD_DELIMITER +
           "Sex" + DATA_DELIMITER + sex + FIELD_DELIMITER;

answered May 9, 2012 at 8:03

Edwin Bautista

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Comments

Mark Yao · Accepted Answer · 2012-05-09 08:16:29Z

0

you can use the code follow:

    String s = "Name:" + name + "Age:" + age + "Sex:" + sex;
    int i = s.indexOf("Age:");
    int j = s.indexOf("Sex:");
    String Name = s.substring(0,i).split(":")[1];
    String Age = s.substring(i,j).split(":")[1];
    String Sex = s.substring(j).split(":")[1];
    System.out.println("Name="+Name+" Age="+Age+" Sex="+Sex);

answered May 9, 2012 at 8:16

Mark Yao

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Comments

Abhishek bhutra · Accepted Answer · 2012-05-09 08:20:49Z

0

I suggest you to use regular expression. Sample code for you is :

String s = "NAME : " + " abhi " + " Age : " + " 22 " + " Sex : " + " m ";
Pattern pattern = Pattern.compile("NAME[\\s]*:[\\s]*(.*)[\\s]*Age[\\s]*:[\\s]*(.*)[\\s]*Sex[\\s]*:[\\s]*(.*)");
Matcher matcher = pattern.matcher(s);
if (matcher.matches()) {
    System.out.println("NAME : " + matcher.group(1) + " Age : " + matcher.group(2) + " Sex : "
            + matcher.group(3));
}

Will work for you .You can do changes for you.

update:And this will work even though their are spaces or not between Name and .Doesnt matter on spaces and dont need to use any delimiter.

edited May 9, 2012 at 8:20

answered May 9, 2012 at 8:12

Abhishek bhutra

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