Testing for array PHP

Question

I created an array below:

$email[] = $post[0];

$email[].= $post[2];

The result is:

$email = Array ( [JESSICA] => [email protected] )

I then pass it to a class constructor as so:

$email_user = new Email($id,$email,$subject,$heading,$messages,$keys);

The class looks like this:

class Email extends Users { 

protected $id;
public $strings;
public $user_email;
public $subject;
public $heading;
public $messages;
public $keys;

public function __construct($id,$user_email,$subject,$heading,$messages,$keys) {

parent::__construct($id);
$this->user_email = $user_email;
$this->subject = $subject;
$this->heading = $heading;
$this->messages = $messages;
$this->keys = $keys;

If I test to see if $this->user_email is an array using:

if(is_array($this->user_email)) {
   echo "TRUE";
}

it returns false. How come?

* I found the issue, a conflict with variables both named $email. Thanks for the help.

@Rocket - I suspect you can, but it'd be the equivalent of $email[] = NULL . ? — Mark Baker
– Mark Baker, Commented May 10, 2012 at 14:45
@MarkBaker: I tested it and the . doesn't do anything. It's the same as $email[] =. — gen_Eric
– gen_Eric, Commented May 10, 2012 at 14:46
@stevenpepe, are you sure that the result in the $email variable is the array you describe? You're not setting the [JESSICA] element anywhere in the example you give. — h00ligan
– h00ligan, Commented May 10, 2012 at 14:49

Kristian · Accepted Answer · 2012-05-10 14:47:41Z

2

Beware that the use of the .= operator is generally used for concatinating two strings.

by saying $email[] = somevalue, you're essentially pushing the value arbitrarily into the array, which is totally good enough for what you're doing. You end up with:

$email[] = $post[0];
$email[] = $post[2];

answered May 10, 2012 at 14:47

Kristian

22k19 gold badges108 silver badges184 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Adam · Accepted Answer · 2012-05-10 14:47:01Z

0

try:

public $user_email = array();

Remove the concatenation: $email[].= $post[2]; $email[] = $post[2]; is fine.

edited May 10, 2012 at 14:47

answered May 10, 2012 at 14:45

Adam

1,69414 silver badges18 bronze badges

Collectives™ on Stack Overflow

Testing for array PHP

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related