Passing multiple values to :not() jQuery?

Question

I want to filter multiple values from an event in jQuery.

At the moment I have:

.filter(":not(.element)")

How would I go about adding more things to filter? I've tried:

.filter(":not(.element, .another, .etc)")

and

.filter(":not(.element)").filter(":not(.another)").filter(":not(.etc)")

and

.filter(":not(.element),:not(.another),:not(.etc)")

With no luck. What do I need to do?

Thanks.

EDIT: Thanks for the answers - I've find another solution to my problem that avoids having to do what I've asked in the question, but evidently I wasn't doing something properly in my code since the solutions posted work. I will mark an answer as correct, many thanks.

All your samples should work, theres something else wrong with your code. — red-X
– red-X, Commented May 14, 2012 at 10:18

Vishal · Accepted Answer · 2012-05-14 10:20:52Z

9

It is working, you just need to separate each element using a comma (,) in the :not() selector.

You can check the example here: http://jsfiddle.net/LVUMs/

answered May 14, 2012 at 10:20

Vishal

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Comments

Rakesh Juyal · Accepted Answer · 2012-05-14 10:22:44Z

4

Looks like it is working. http://jsbin.com/uyayot/edit#javascript,html

I tried:

$('div').not('#div2,#div4').each ( function () {
    alert ( $(this).attr ('id' ) );
  });

answered May 14, 2012 at 10:22

Rakesh Juyal

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Comments

Ashwin Krishnamurthy · Accepted Answer · 2012-05-14 10:24:07Z

2

You can use not() by chaining it. Like this

$('yourElement').not(':even').not('.SomeMore').not('.fewmore')

edited May 14, 2012 at 10:24

Ashwin Krishnamurthy

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answered May 14, 2012 at 10:13

Ravi Gadag

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1 Comment

zerkms Over a year ago

Even though it would work - it doesn't explain why other OP's attempts failed

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