Using a variable inside an included file from function

Question

I'd like to have a header.php file throughout my site. I currently have the following:

header.php

<head>
    <meta charset="utf-8">
    <link rel="stylesheet" href="<?php if(isset($depth)){echo $depth;};?>css/style.css">

functions.php

function include_layout_template($template="", $depth="")
{
    global $depth;
    include(SITE_ROOT.DS.'public'.DS.'layouts'.DS.$template);
}

index.php

<?php include_layout_template('header.php', "../"); ?>

But $depth dissappears, I can't even echo $depth; its just blank. How can I get the depth variable for use in header.php?

$depth is both a global variable and a parameter to the function include_layout_template? that must be messing things up... — Yaniro
– Yaniro, Commented May 14, 2012 at 11:37

Sergey · Accepted Answer · 2012-05-14 11:38:36Z

2

You have to rename depth variable in function call

function include_layout_template($template="", $my_depth="")
{
   global $depth;
   //if need $depth = $mydepth

answered May 14, 2012 at 11:38

Sergey

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Comments

Starx · Accepted Answer · 2012-05-14 11:45:10Z

0

Your $depth variable is disappearing, because it is passed as parameter first but then defined to use the global parameter.

I will explain with an example:

$global = "../../"; //the variable outside
function include_layout_template($template="", $depth="")
{
    global $depth; //This will NEVER be the parameter passed to the function
    include(SITE_ROOT.DS.'public'.DS.'layouts'.DS.$template);
}
include_layout_template("header.php", "../");

To solve, simply modify the function parameter other than the depth itself.

function include_layout_template($template="", $cDepth="") { }

answered May 14, 2012 at 11:45

Starx

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