Remove partial string in Shell Script

Question

How can I remove price from following data in Shell Script? I am printing labels and don't want to show price.

Input:

Order: 12
Name: Raj K
ABC Inc
123 Main St
Edison NJ

1 Printer - $50.09
Router - $30.00
2 AirPrint - $56.10

Output

Order: 12
Name: Raj K
ABC Inc
123 Main St
Edison NJ

1 Printer
Router
2 AirPrint

Any ideas?

What tools do you have (sed/awk/perl/bash/...), are the prices always exactly like that, and what have you tried so far? — Mat
– Mat, Commented May 14, 2012 at 18:34
I was using few pattern match in sed but no luck. The shell is bash. I think, I can use perl in the shell script as well, if there is an easy way to do it. — VKA
– VKA, Commented May 14, 2012 at 18:37
Please include the things you tried in your question. This will allow people to tell you where you got it wrong and/or how you can do it better. You'll learn more that way. — Mat
– Mat, Commented May 14, 2012 at 18:38
The solution below given by Tim works with sed. I was using wrong pattern matches. Thank you. — VKA
– VKA, Commented May 14, 2012 at 18:39

Tim Pote · Accepted Answer · 2012-05-14 19:08:48Z

1

Use sed:

sed '/ *- *\$[0-9]\+\.[0-9]\{2\}/s///' file

^{This has been updated in response to Glenn's comment below.}

answered May 14, 2012 at 18:29

Tim Pote

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2 Comments

You could also take advantage of sed's use of an empty regex re-using the previous one: sed '/ \+- \+\$[[:digit:]]\+\.[[:digit:]]\{2\}/s///'

@glennjackman B.A. I had no idea that existed. Edited per your recommendation.