php array foreach loop skipping a single key value

Question

I am trying to get a foreach loop to display all the values of an array but for some reason it skips value 4.

echo $sku."<br>";
$skuArray = explode(" ", $sku);
$skuCount = array_count_values($skuArray);
print_r($skuArray);
echo "<br><br>";
$i=0;
foreach ($skuCount as $key => $val) {
    echo "[".$i."] => ".$key." ";
    $i++;
}

and this is what the output looks like:

1DALI0SPBA775RW 2 $92.99 1GJESSGRIP10000 2 $9.99

Array ( [0] => 1DALI0SPBA775RW 
        [1] => 2 
        [2] => $92.99 
        [3] => 1GJESSGRIP10000 
        [4] => 2 
        [5] => $9.99 )

[0] => 1DALI0SPBA775RW 
[1] => 2 
[2] => $92.99 
[3] => 1GJESSGRIP10000 
[4] => $9.99

As you can see, the foreach loop says that 4 is equal to $9.99 but in the print_r array it is equal to 2 - which is what I expect it to be.

array_count_values sums the number of times a particular element appears in the array. — Explosion Pills
– Explosion Pills, Commented May 15, 2012 at 18:01
The issue is your foreach is looking at skuCount, why not do your foreach on skyuArray? — DaOgre
– DaOgre, Commented May 15, 2012 at 18:04

Nathaniel Ford · Accepted Answer · 2012-05-15 18:07:13Z

3

This is what you want:

echo $sku."<br>";
$skuArray = explode(" ", $sku);
print_r($skuArray);
echo "<br><br>";
$i=0;
foreach ($skuArray as $key => $val) {
    echo "[".$key."] => ".$val." ";
}

array_count_values($skuArray) actually creates an array you can loop through, but with duplicates elided to a single value. See the documentation.

answered May 15, 2012 at 18:07

Nathaniel Ford

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