Adding some numbers in Shell Script?

Question

How can I get the sum of the following number? They are getting multiplied before getting added.

Input File (count.txt)
2*4
2*1
3*1
3*1
2*1
2*1

Command I am using:
( echo 0 ; sed 's/$/ +/' count.txt; echo p ) | dc.

The Sum I am getting is 343 which is not correct. I am expecting 20 as sum.

2*4
2*1
3*1
3*1
2*1
2*1

Sum: 20 (Multiplication and then sum for each line)

Any ideas?

Thanks, Raj

Ander2 · Accepted Answer · 2012-05-15 21:51:33Z

1

This will also do the job:

awk -F'*' '{i+=$1*$2} END{print i}' count.txt

answered May 15, 2012 at 21:51

Ander2

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Comments

loscuropresagio · Accepted Answer · 2012-05-15 21:39:59Z

1

This should do the job:

cat count.txt | tr \\n \+ | sed 's/$/\n/' | bc

be sure that there's no new line at the end of file, otherwise you must modify the sed expression.

answered May 15, 2012 at 21:39

loscuropresagio

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Rawkode · Accepted Answer · 2012-05-15 21:30:56Z

0

cat count | while read line; do echo $(($line)); done | awk '{i+=$1} END {print i}'

This is the best solution I could come up with, hope it helps.

answered May 15, 2012 at 21:30

Rawkode

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