java string split regular expression

Question

I have a string (1, 2, 3, 4), and I want to parse the integers into an array.

I can use split(",\\s") to split all but the beginning and ending elements. My question is how can I modify it so the beginning and ending parenthesis will be ignored?

Have you thought about looking at the substring from 1 to length-2? If you do this, then the string should be separable with split. — pippin1289
– pippin1289, Commented May 16, 2012 at 18:31

Marko Topolnik · Accepted Answer · 2012-05-16 18:34:29Z

3

You'd be better served by matching the numbers instead of matching the space between them. Use

final Matcher m = Pattern.compile("\\d+").matcher("(1, 2, 3, 4)");
while (m.find()) System.out.println(Integer.parseInt(m.group()));

answered May 16, 2012 at 18:34

Marko Topolnik

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1 Comment

Tony Ennis Over a year ago

The less reliable the data, the better this solution.

AlexR · Accepted Answer · 2012-05-16 18:34:21Z

2

Use 2 regexes: first that removes parenthesis, second that splits:

Pattern p = Pattern.compile("\\((.*)\\)");
Matcher m = p.matcher(str);
if (m.find()) {
    String[] elements = m.group(1).split("\\s*,\\s*");
}

And pay attention on my modification of your split regex. It is much more flexible and safer.

answered May 16, 2012 at 18:34

AlexR

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Comments

pippin1289 · Accepted Answer · 2012-05-17 22:42:46Z

1

You could use substring() and then split(",")

  String s = "(1,2,3,4)";
  String s1 = s.substring(1, s.length()-2);//index should be 1 to length-2
  System.out.println(s1);

  String[] ss = s1.split(",");
  for(String t : ss){
    System.out.println(t);
  }

edited May 17, 2012 at 22:42

pippin1289

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answered May 16, 2012 at 18:40

ChadNC

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Comments

Alex Moore · Accepted Answer · 2012-05-18 02:27:15Z

0

Change it to use split("[^(),\\s]") instead.

edited May 18, 2012 at 2:27

Alex Moore

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answered May 16, 2012 at 18:32

ControlAltDel

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1 Comment

AlexR Over a year ago

This will create 2 extra elements: empty strings in the beginning and end.

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