How tp parse Json result which is returned with an arraylist in a webmethod?

Question

This is a simplified code. I have a webservice (.asmx) as following: I store some values in Test class and then store the class in an arraylist.
I do this two times in two different arraylists. and then store these two array lists in a third arraylist. and then pass this arraylist as output of webmethod.

 private class Test
        {
            public string Id;
            public string Name;
        }

[webmethod]

      public ArrayList RuleReport(long RuleId)
    {
        Test t = new Test();
        t.Id = "1";
        t.Name = "a";

        ArrayList ar = new ArrayList();
        ArrayList ar2 = new ArrayList();
        ArrayList ar3 = new ArrayList();

        ar.Add(t);

t = new Test();
        t.Id = "2";
        t.Name = "b";
        ar2.Add(t);
        ar3.Add(ar);
        ar3.Add(ar2);
        return ar3;
    }

and in js file I want to parse he json result to read each Id and Name values of two arraylists.

id=1,name=a
id=2,name=b

this is my jquery code:

 $.ajax(
{ url: " Ajaxes/Rules.asmx/RuleReport",
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    type: "POST",
    data: "{'RuleId':'79'}",
    async: false,
    success: function(data) {
    $.each(data.d, function(index, obj) {
    alert(obj.d[0].Id);// something like this. How to do it???
        })

    }, error: function() { }
});

this is the json response in fire bug:

{"d":[[{"Id":"1","Name":"a"}],[{"Id":"2","Name":"b"}]]}

how to get every Id and Name values???

Prasenjit Kumar Nag · Accepted Answer · 2012-05-19 13:38:43Z

3

With your current setup inside $.each loop you are getting

[{"Id":"1","Name":"a"}]

as obj. As you can see it's a array of object with only one object as it's content. You can access that object with obj[0] and then their properties can be accessed with obj[0].Id and obj[0].Name

You can do this with the following code

$.each(data.d,function(index,obj){

       var id = obj[0].Id;
       var name = obj[0].Name;
       // do what ever you want with them
   })

Working fiddle

answered May 19, 2012 at 13:38

Prasenjit Kumar Nag

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