passing a lua table from C++ to .Lua script

Question

I have spent the past 6 hours trying to solve this ! and i coulnt get anywhere :s

I want to be able to create a lua table in a c++ file and then pass that to a lua script file, which has the following lua function:

function MTable (t) 
local n=#t
    for i=1,n do 
      print(t[i]) 
    end
end

i dynamically created a one dimensional array with two strings:

 lua_newtable(L);
 lua_pushstring(L,"10.10.1.1");
 lua_pushstring(L,"10.10.1.2");
 lua_rawseti(L,-3,2);
 lua_rawseti(L,-2,1);

so now i have the table on top of the stack. I have verified it by writting this : if( lua_istable(L,lua_gettop(L)))` which returned 1, which means it is a table.

then I did this:

lua_getglobal(L, "MTable");    // push the lua function onto the stack

uint32_t   result = lua_pcall(L, 1, 0, 0);  //argument 1 is for the table
 if (result) {
 printf(stderr, "Failed to run script: %s\n", lua_tostring(L, -1));
         exit(1);
}

so I got that error: Failed to run script: attempt to call a table value

Kindly note that the file has several other functions that i am calling successfully from c++.

can somebody please help me solve this error ? can this be a bug from LUA? cz i followed the steps very correctly...i guess !

snogglethorpe · Accepted Answer · 2012-05-20 02:55:15Z

4

The function has to be first on the stack, before the args.

You can either:

push the function to call on the stack before generating the table, e.g.:

lua_getglobal(L, "MTable");
...generate table on stack...
int result = lua_pcall(L, 1, 0, 0);

Do in the order you do now, and then just swap the arg and the function prior to doing the pcall:

...generate table on stack...
lua_getglobal(L, "MTable");
lua_insert (L, -2);   // swap table and function into correct order for pcall
int result = lua_pcall(L, 1, 0, 0);

answered May 20, 2012 at 2:55

snogglethorpe

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