Loading JavaScript when div has loaded?

Question

I have a script that will reload the page (content) to a random DIV How do I implement this so that the script loads after the div is loaded?

I have the following code ready:

<script>  
$(document).ready(function() {
   $("#getAssignment").click(function() {
      var $divs = $(".assignment");
      if ($divs.length > 0) {
         window.location.hash = "#" + $divs[ Math.floor(Math.random() * 
         $divs.length) ].id;
      }
  });
});    
</script>

This question is not very clear. Do you have code that is dynamically loading content into a div? If so, please show that code. — jfriend00
– jfriend00, Commented May 21, 2012 at 4:30
div's don't load. div's are just part of the larger page. If you're changing what's inside a div, then whatever code is doing that can trigger whatever you want to happen afterward... — Mark Reed
– Mark Reed, Commented May 21, 2012 at 4:44
sorry, this script is usually done when the user click on a button and the script will then select a random div from a list of them (they are classes as "assignment") I want to do the same thing, but instead when this particular page(which is a DIV) is loaded — Noel Chenier
– Noel Chenier, Commented May 21, 2012 at 4:45

Derek 朕會功夫 · Accepted Answer · 2012-05-21 05:28:03Z

1

$("div").load(function(){
    blah();
});

This will do what you wanted, but it does not make sense though, since div is not like an image or <script> or a page. (You can't really "load" a <div> anyway.)

edited May 21, 2012 at 5:28

answered May 21, 2012 at 4:25

Derek 朕會功夫

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5 Comments

Noel Chenier Over a year ago

sorry guys, I'm really stupid when it comes to code...how do I make the onload function work with what I have?

Noel Chenier Over a year ago

sorry, this script is usually done when the user click on a button and the script will then select a random div from a list of them (they are classes as "assignment") I want to do the same thing, but instead when this particular page(which is a DIV) is loaded.

Mark Reed Over a year ago

A page is not a DIV. That makes no sense. Pages contain divs.

Noel Chenier Over a year ago

forgive me for using the wrong terminology. What I am using this for is app created in Dreamweaver using phonegap. So how can I trigger this script when this div is revealed/made active/whatever? @Derek is the "div" part in that the name of the div?

Derek 朕會功夫 Over a year ago

@user1114118 - $("div") means every <div>.

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