JAVA_HOME and java -version

Question

I'm using a Windows .bat script and I set JAVA_HOME as C:/Program Files/Java/jdk1.6.0_32 when I do a java -version, it still shows the 1.3

How can I fix this? What am I doing wrong?

It doesn't give any error btw

user1345883
– user1345883

2012-05-21 14:23:08 +00:00
Commented May 21, 2012 at 14:23 — user1345883
– user1345883, Commented May 21, 2012 at 14:23
Show output of echo %PATH%.

Andrew Logvinov
– Andrew Logvinov

2012-05-21 14:23:58 +00:00
Commented May 21, 2012 at 14:23 — Andrew Logvinov
– Andrew Logvinov, Commented May 21, 2012 at 14:23
That isn't enough. Prepend JAVA_HOME\bin to PATH.

hmjd
– hmjd

2012-05-21 14:25:29 +00:00
Commented May 21, 2012 at 14:25 — hmjd
– hmjd, Commented May 21, 2012 at 14:25

TheBakker · Accepted Answer · 2017-02-10 10:41:54Z

18

For me the issue was in my PATH variable, C:\ProgramData\Oracle\Java\javapath; was added by java windows install before my %JAVA_HOME%\bin;. So I'd echo %JAVA_HOME% pointing to a JDK7 and java -version showing jdk8.

I'd to put %JAVA_HOME%\bin; before C:\ProgramData\Oracle\Java\javapath; so that java -version displays jdk7.

answered Feb 10, 2017 at 10:41

TheBakker

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Comments

Aaron Digulla · Accepted Answer · 2012-05-21 14:27:34Z

11

Try %JAVA_HOME%\bin\java -version

If you modify JAVA_HOME, it's usually better to invoke java with an absolute path (using JAVA_HOME) because the new binary is probably not in the path (and then Windows will load the wrong binary).

answered May 21, 2012 at 14:27

Aaron Digulla

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Óscar López · Accepted Answer · 2012-05-21 14:25:13Z

6

Make sure that the PATH environment variable is pointing to %JAVA_HOME%\bin.

answered May 21, 2012 at 14:25

Óscar López

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soorapadman · Accepted Answer · 2017-08-24 07:10:24Z

2

Be sure not to mix the system variable path and the user variable system path. I feel OK in calling java without the absolute path (when I know how JAVA_HOME and PATH are configured).

edited Aug 24, 2017 at 7:10

soorapadman

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answered Oct 24, 2012 at 21:20

A_rnO

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npe · Accepted Answer · 2012-05-21 14:26:45Z

0

Calling java -version from command line, causes cmd.exe to do the lookup on the "known" directories. "Known" means PATH environment variable. It seems that your PATH contains a java 1.3 bin folder, and not 1.6.

JAVA_HOME is another variable, that is used (for example, and not only) by java wrappers, or by scripts executing some java stuff.

Try doing this:

SET JAVA_HOME=C:/Program Files/Java/jdk1.6.0_32
%JAVA_HOME%/bin/java -version

Add quotes where needed.

answered May 21, 2012 at 14:26

npe

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rajeev pani.. · Accepted Answer · 2017-05-06 15:40:29Z

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I had similar issue,in my case , I had two versions java installed. it can be fixed by uninstalling one version of java completely from system.

answered May 6, 2017 at 15:40

rajeev pani..

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DanBot · Accepted Answer · 2019-12-11 10:26:37Z

0

Had a similar scenario today - two Windows 10 devices - both have JRE 1.6 & 1.7.

When typing

 Java -version

One device shows 1.6 the other 1.7.

This was preventing me running a third party JAR to install some software on the device showing 1.6 (which worked fine on the device showing 1.7 when running java -version), using:

  java -jar ThirdParty.jar

As the JAR needed to be run by 1.7.

Cause of this was in the PATH environment variable - one device had the location of 1.6 first in the PATH list, moving the 1.7 location above the 1.6 location resulted in consistency using Java -version and allowed me to install the software.

answered Dec 11, 2019 at 10:26

DanBot

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pedagogyfirst · Accepted Answer · 2022-06-23 23:45:49Z

0

java -version will consult the paths in the special environment variable Path. You need to select the java version you want and move it upwards the latter (click "Move Up"). You probably have that reference to JDK 1.3 in Path above your addition of JDK 1.6. Since that's the first thing the OS finds, that's what it chooses to run.

Executing the command again with the same window opened after changing the environment variables will not work. Re-open it

I know this question is old but this was my case and I wanted to re-explain further, similar to @DanBot 's case

answered Jun 23, 2022 at 23:45

pedagogyfirst

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