How to get with JAVA a specific value for one substring from string?

Question

I have ONE string field which is in format:

"TransactionID=30000001197169 ExecutionStatus=6
        additionalCurrency=KMK
    pin= 0000"

So they are not separated with some ; оr , they are not seperated even with one blank space.

I want to get value for Execution Status and put it in some field? How to achieve this?

Thanks for help

JackAss · Accepted Answer · 2012-05-22 07:36:47Z

3

This works. But I am not sure this is the most optimal.It just solves your problem.

    String s = "TransactionID=30000001197169ExecutionStatus=6additionalCurrency=KMKpin=0000";
    if(s!=null && s.contains("ExecutionStatus="))
    {
        String s1[] = s.split("ExecutionStatus=");
        if(s1!=null &&  s1.length>1)
        {
            String line = s1[1];
            String pattern = "[0-9]+";

              // Create a Pattern object
              Pattern r = Pattern.compile(pattern);

              // Now create matcher object.
              Matcher m = r.matcher(line);
              if (m.find( )) {
                 System.out.println("Match");
                 System.out.println("Found value: " + m.group(0) );

              } else {
                 System.out.println("NO MATCH");
              }
        }
    }

answered May 22, 2012 at 7:36

JackAss

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2 Comments

JackAss Over a year ago

The above code is dynamic. It does not matter what comes after 6 or what comes before ExecutionStatus= . It will only search for the value of ExecutionStatus as you desired

JackAss Over a year ago

As you can see the code has used regular expression. it searches [0-9+] means any length of numeric value.

Herm · Accepted Answer · 2012-05-22 07:38:12Z

2

In your example they are indeed seperated by blanks, but the following should be working without blanks, too. Assuming your String is stored in String arguments

String executionStatus;
String[] anArray = arguments.split("=");
for (int i; i < anArray.length; i++)
    if (anArray[i].contains("ExecutionStatus")){
        executionStatus = anArray[++i].replace("additionalCurrency","");
        executionStatus = executionStatus.trim();
    }
}

edited May 22, 2012 at 7:38

answered May 22, 2012 at 7:32

Herm

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3 Comments

Veljko Over a year ago

my result is "6 additionalCurrency" so I must cut additionalCurrency from result

Veljko Over a year ago

yes thanks. one small question - what if additionalCurrency is not always the second parameter in string? Thanks for help

Herm Over a year ago

first, it doesn't matter, which place executionStatus is. You should trim the string correctly, when the order can change. either you replace all occurences of parameters like "additionalCurrency" with "", or you trim the string with other options (possibily a blank yet).

Jigar Joshi · Accepted Answer · 2012-05-22 07:21:20Z

2

Check if it contains() ExecutionStatus=

If yes then split the string with ExecutionStatus=

Now take the Second string from array find the first occurance of non digit char and use substring()

answered May 22, 2012 at 7:21

Jigar Joshi

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2 Comments

Veljko Over a year ago

can you write me the shortest cod for this? sorry for disturbing

Jigar Joshi Over a year ago

I have given enough(dirty) information, Please check api doc and try to write by yourself

flesk · Accepted Answer · 2012-05-22 07:45:40Z

1

Assuming all that white space is present in your string, this works.

String str = "\"TransactionID=30000001197169 ExecutionStatus=6\n" +
        "        additionalCurrency=\"KMK\"\n" +
        "    pin= \"0000\"\"";
int start = str.indexOf("ExecutionStatus=") + "ExecutionStatus=".length();
int status = 0;

if (start >= 0) {
    String strStatus = str.substring(start, str.indexOf("additionalCurrency=") - 1);
    try {
        status = Integer.parseInt(strStatus.trim());
    } catch (NumberFormatException e) {
    }
}

answered May 22, 2012 at 7:45

flesk

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Comments

Anthony Roy · Accepted Answer · 2012-05-22 08:31:12Z

1

At the risk of attracting "... and now you have two problems!" comments, this is probably easiest done with regexes (str is the String defined above):

Pattern p = Pattern.compile("ExecutionStatus\\s*=\\s*(\\d+)"); // Whitespace matching around equals for safety, capturing group around the digits of the status)
Matcher m = p.matcher(str);
String status = m.find() ? m.group(1) : null;

answered May 22, 2012 at 8:31

Anthony Roy

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