Sending file from iOS to PHP using POST

Question

I'm trying to send an audio file to a PHP server. Here is the Objective-C code:

NSData *data = [NSData dataWithContentsOfFile:filePath];

NSLog(@"File Size: %i",[data length]);

//set up request
NSMutableURLRequest *request= [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:urlString]];
[request setHTTPMethod:@"POST"];

//required xtra info
NSString *boundary = @"---------------------------14737809831466499882746641449";
NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@", boundary];
[request addValue:contentType forHTTPHeaderField: @"Content-Type"];

//body of the post
NSMutableData *postbody = [NSMutableData data];
[postbody appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]];
[postbody appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"thefile\"; filename=\"recording\"\r\n"] dataUsingEncoding:NSUTF8StringEncoding]];
[postbody appendData:[[NSString stringWithString:@"Content-Type: application/octet-stream\r\n"] dataUsingEncoding:NSUTF8StringEncoding]];
[postbody appendData:data];
[postbody appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]];

[request setHTTPBody:postbody];
apiConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self];

And here is the PHP code:

if (is_uploaded_file($_FILES['thefile']['tmp_name'])) {
    echo "FILE NAME: ".$_FILES['thefile']['name'];
} else {
    echo "Nothing";
}

The File Size varies depending on the length of audio being recorded, but there is data.

I'm getting a response of "Nothing".

Sunny · Accepted Answer · 2012-05-23 18:01:58Z

7

To debug: on the PHP side, try:

$file = $_POST['name'];
echo $file

Try the following code segment in place of your current code. Change the url (www.yourWebAddress.com) and script name to appropriate values for your problem.

NSData *data = [NSData dataWithContentsOfFile:filePath];
NSMutableString *urlString = [[NSMutableString alloc] initWithFormat:@"name=thefile&&filename=recording"];
[urlString appendFormat:@"%@", data];
NSData *postData = [urlString dataUsingEncoding:NSASCIIStringEncoding 
                                   allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];
NSString *baseurl = @"https://www.yourWebAddress.com/yourServerScript.php"; 

NSURL *url = [NSURL URLWithString:baseurl];
NSMutableURLRequest *urlRequest = [NSMutableURLRequest requestWithURL:url];
[urlRequest setHTTPMethod: @"POST"];
[urlRequest setValue:postLength forHTTPHeaderField:@"Content-Length"];
[urlRequest setValue:@"application/x-www-form-urlencoded" 
          forHTTPHeaderField:@"Content-Type"];
[urlRequest setHTTPBody:postData];

NSURLConnection *connection = [NSURLConnection connectionWithRequest:urlRequest delegate:self];
[connection start];

NSLog(@"Started!");

On the server end, I have the following code:

<?php

    $name  = $_POST['name'];
    $filename  = $_POST['filename'];
    echo "Name = '" . $name . "', filename = '" . $filename . "'.";

    error_log ( "Name = '" . $name . "', filename = '" . $filename . "'." );

?>

I received the following output:

[23-May-2012 11:56:18] Name = 'thefile', filename = 'recording'.

I don't know why it is not working for you. You must have a missing step. Try commenting out the two lines in the url POST code above that references 'data' to see that you can get at the least the plain text for name and filename to your server end.

Good luck!

edited May 23, 2012 at 18:01

answered May 22, 2012 at 23:34

Sunny

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13 Comments

Chris Over a year ago

Sunny, the file name is blank.

Sunny Over a year ago

Ok, I've updated my answer. Try my code to see how it works for you.

Sunny Over a year ago

Oops. I have fixed the typo from cutting and pasting for: "NSMutableString *urlString = [[NSMutableString alloc] initWithFormat:@"name=thefile&&filename=recording"];"

Chris Over a year ago

Also blank. To make sure it's reaching the server, I added FILE NAME: to the echo.

Sunny Over a year ago

I tested your link moments ago. I got back "Name = 'thefile', filename = 'recording'." on my app NSURLConnection -(void)connection:(NSURLConnection*)connection didReceiveData:(NSData*)data delegate. However, if your site does not support https, then make sure that you change the baseURL from "NSString *baseurl = @"https://..";" to "NSString *baseurl = @"http://...";" Also, make sure you declared that your viewController implements NSURLConnectionDelegate. Good luck!

|

Community · Accepted Answer · 2017-05-23 12:01:29Z

1

Try encoding your binary data before you send it over the pipe (and then decode when it gets to the other end). See this SO thread for ideas for Base64 encoding code.

edited May 23, 2017 at 12:01

CommunityBot

11 silver badge

answered May 22, 2012 at 23:32

Alex Reynolds

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Comments

kalpesh · Accepted Answer · 2017-01-23 04:56:27Z

In swift you can post like this..

    func wsPostData(apiString: String, jsonData: String) -> Void
    {
         //apiString means base URL
        let postData = jsonData.dataUsingEncoding(NSASCIIStringEncoding, allowLossyConversion: true)
        let postLenth = "\(UInt((postData?.length)!))"
        let request = NSMutableURLRequest()
        request.URL = NSURL(string: apiString)
        request.HTTPMethod = "POST"
        request.setValue(postLenth, forHTTPHeaderField: "Content-Lenth")
        request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
        request.HTTPBody = postData
        NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue()) { (response: NSURLResponse?, data: NSData?, error:NSError?) in

            print("response\(response)")
            var dict:NSDictionary!
            do {
                dict = try NSJSONSerialization.JSONObjectWithData(data!, options: []) as? [String: AnyObject]
                print(" responce data is \(dict)")
            }
            catch let error as NSError
            {
                print("Something went wrong\(error)")
            }

        }
    }

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