Variable not expanding in Perl string?

Question

i am trying to copy a png file using the next code

$cty2 = 'filename';
fwrite($fh, $stringData);
$old = 'images/bg_freeze.png';
$new = 'images/$cty2.png';
copy($old, $new) or die("Unable to copy $old to $new.");
fclose($fh);

But, the result is a png file with this name ( $cty2.png ) it should be ( filename.png )

How I solve it to make the new file name ( filename.png ) not ( $cty2.png )

I have edited as Perl-related (jumped the gun :-/), please correct if in error. — user166390
– user166390, Commented May 23, 2012 at 0:02

Oliver Charlesworth · Accepted Answer · 2012-05-22 23:38:15Z

11

You haven't specified which language. But the problem is almost certainly that you need to use double-quotes ("), not single-quotes ('). Otherwise variables will not be expanded inside the string.

answered May 22, 2012 at 23:38

Oliver Charlesworth

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1 Comment

Hatim Over a year ago

$old = "images/bg_freeze.png"; $new = "images/$cty2.png";

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