Jquery function consumes the array

Question

I don't quite understand what's wrong with my function that I wrote,

When I pass an array to it, eg:

var pvars=['health/1/1.jpg','health/1/2.jpg','health/1/3.jpg','health/1/4.jpg'];
cache_threads(pvars,1);

Then I end up with an empty variable, eg:

alert(pvars);

Returns an empty string.

Here is my function:

var cache_threads=function (arruy,quant){
    if (quant==undefined) quant=1;
var div=Math.ceil(arruy.length/quant);
var a = arruy;
while(a.length) {
    cache_bunch(a.splice(0,div));
}
}

Alnitak · Accepted Answer · 2012-05-26 21:49:36Z

1

a and arruy are the same array.

When you .splice one, you'll be splicing the other one, too!

If you want a (shallow) copy of the array, use .slice():

var a = arruy.slice(0);

edited May 26, 2012 at 21:49

answered May 26, 2012 at 21:44

Alnitak

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1 Comment

Anonymous Over a year ago

Yeah, I should have thought of that... would you suggest any solution to it?

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