Build JSON Object from string containing multi-dimensional

Question

I have an array of name/value objects (below). The names are formatted to represent multi-dimensional array.

I need to build a full JavaScript object out of it(bottom).

[{
name: "getQuote[origin]",
value: "Omaha,NE"
}, 
{
name: "getQuote[destination]",
value: "10005"
}, 
{
name: "getQuote[country]",
value: "us"
}, 
{
name: "getQuote[vehicles][0][year]",
value: "1989"
},
{
name: "getQuote[vehicles][0][make]",
value: "Daihatsu"
}, 
{
name: "getQuote[vehicles][0][model]",
value: "Charade"
}, 
{
name: "getQuote[vehicles][0][count]",
value: "1"
}]

Into something like this:

{getQuote : 
  { origin : Omaha},
  { destination : 10005},
  {vehicles : [
   {
    year : 1989,
    make: Honda,
    model : accord
   },
   {
   //etc
}]

n

There's no such thing as "JSON object". You will most likely want just "object". — Oleg V. Volkov
– Oleg V. Volkov, Commented Jun 5, 2012 at 15:42
Well, it doesn't seems to be that hard to split it by [] blocks and auto-vivify objects on demand. The only tricky part would be is to vivify Array object for levels where only numeric indices are used. — Oleg V. Volkov
– Oleg V. Volkov, Commented Jun 5, 2012 at 16:04
@OlegV.Volkov, that's what is the problem! it doesn't seem to be that hard, but try solving it, it will surely eat your brain up. I am trying to solve it since last 15+ minutes, not even close to the solution! — Parth Thakkar
– Parth Thakkar, Commented Jun 5, 2012 at 16:07
to break things up I am doing this: strAry = myArray[i].replace(/\]/g, "").split("["); But that is only part of the puzzle. — Dean Peterson
– Dean Peterson, Commented Jun 5, 2012 at 16:11

Dmytro Shevchenko · Accepted Answer · 2012-06-05 16:17:01Z

2

You can do it manually, like this:

var source = [ /* Your source array here */ ];
var dest = {};

for(var i = 0; i < source.length; i++)
{
    var value = source[i].value;

    var path = source[i].name.split(/[\[\]]+/);

    var curItem = dest;

    for(var j = 0; j < path.length - 2; j++)
    {
        if(!(path[j] in curItem))
        {
            curItem[path[j]] = {};
        }

        curItem = curItem[path[j]];
    }

    curItem[path[j]] = value;
}

dest is the resulting object.

Check it working here: http://jsfiddle.net/pnkDk/7/

answered Jun 5, 2012 at 16:17

Dmytro Shevchenko

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3 Comments

Parth Thakkar Over a year ago

sweet! short and really nice!

Dean Peterson Over a year ago

MMmm, some new things I haven't seen before thanks. The solution I had wasn't nearly as elegant as this. Gold Stars for you, Shedal.

Bergi Over a year ago

This does not create Arrays for numerical indizes, as it should. I think you can easily fix that.

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