How to remove digit () using regex in php?

Question

I have a sample code:

Acer phones (36)
Yezz phones (13)
Nokia phones (371)
Apple (1)

How to remove (digit) in this text I am using preg_replace("^$d$$", "", $name[$i]); // With $name[$i] is Acer phones (36), Yezz phones (13)...

\d+, not just d

k102
– k102

2012-06-07 07:51:48 +00:00
Commented Jun 7, 2012 at 7:51 — k102
– k102, Commented Jun 7, 2012 at 7:51

STT LCU · Accepted Answer · 2012-06-07 08:04:11Z

2

Use this example, which is a small adaptation from your attempt:

$a = "Acer phones (36)";
$a = preg_replace("#\(\d+\)$#", "", $a);

the # are the pattern delimiters (required by PHP, you can pick almost any character you want)

the ^ has been removed, because you don't need to look from the exact start of the string, but $ has been kept because the (NN) is at the end of the string

"d" has been replaced by \d+ (remember to always escape special regex character, you forgot the escape in your example

edited Jun 7, 2012 at 8:04

answered Jun 7, 2012 at 7:56

STT LCU

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flowfree · Accepted Answer · 2012-06-07 07:55:19Z

1

You're almost there:

preg_replace("/\(\d+?\)$/", "", $name[$i]);

answered Jun 7, 2012 at 7:55

flowfree

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