See this code:
<?php
$a = rand(1, 10000000000);
$b = "abcdefghi";
?>
How can I insert $b into a random position of $a?
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3Define "casual position". Do you mean a random position?Evan Mulawski– Evan Mulawski2012-06-07 16:31:34 +00:00Commented Jun 7, 2012 at 16:31
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5 Answers
Assuming "casual" means random:
<?php
$a = rand(1, 10000000000);
$b = "abcdefghi";
//get a random position in a
$randPos = rand(0,strlen($a));
//insert $b in $a
$c = substr($a, 0, $randPos).$b.substr($a, $randPos);
var_dump($c);
?>
above code working: http://codepad.org/VCNBAYt1
Edit: had the vars backwards. I read "insert a into b,
1 Comment
Jonathan Kuhn
@AldoHolm I read the OP backwards, the original code would insert $a into $b. fixed the code so it does $b into $a.
I guess you could by treating $a as a string and concatenating it with $b:
$a = rand(1, 1000000);
$b= "abcd";
$pos = rand(0, strlen($a));
$a = substr($a, 0, $pos).$b.substr($a, $pos, strlen($a)-$pos);
and the results:
a=525019
pos=4
a=5250abcd19
a=128715
pos=5
a=12871abcd5
Comments
You should put {$b} on top of {$a} so that you can insert it to {$b}.. eg:
<?php
$b = "abcdefghi";
$a = rand(1, 10000000000);
$a .= $b;
echo $a;
?>
2 Comments
Jonathan Kuhn
what exactly does the order the variables are defined have to do with anything? As long as both variables are defined by the time you use them, order doesn't matter.
Aldo Holm
Tnks but this isn't random position
Sth like this :
<?php
$position = GetRandomPosition(); // you will have to implement this function
if($position >= strlen($a) - 1) {
$a .= $b;
} else {
$str = str_split($a, $position);
$a = $str[0] . $b . implode(array_diff($str, array($str[0])));
}
?>
Comments
Cast $a to string, then use strlen to get the length of $a. Use rand, with with the length of $a as the maximum, to get a random position within $a. Then use substr_replace to insert $b into $a at the position you've just randomized.
