jQuery/JSON/PHP failing

Question

I am trying to call a php script that accepts JSON data, writes it into a file and returns simple text response using jQuery/AJAX call.

jQuery code :

   $("input.callphp").click(function() {
    var url_file = myurl;
    $.ajax({type : "POST",
            url : url_file,
            data : {puzzle: 'Reset!'},
            success : function(data){
                alert("Success");
                alert(data);
            }, 
            error : function (jqXHR, textStatus, errorThrown) {
                alert("Error: " + textStatus + "<" + errorThrown + ">");
            },
            dataType : 'text'
    });
});

PHP Code :

<?php
  $thefile = "new.json"; /* Our filename as defined earlier */
  $towrite = $_POST["puzzle"]; /* What we'll write to the file */
  $openedfile = fopen($thefile, "w");
  fwrite($openedfile, $towrite);
  fclose($openedfile);
  echo "<br> <br>".$towrite;
?>

However, the call is never a success and always gives an error with an alert "Error : [Object object]".

NOTE

This code works fine. I was trying to perform a cross domain query - I uploaded the files to the same server and it worked.

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

var url_file = myurl"; // remove `"` from end

Arguments of error function is:

.error( jqXHR, textStatus, errorThrown )

not data,

You can get data (ie. response data from server) as success() function argument.

Like:

success: function(data) {

}

For more info look .ajax()

NOTE

If you're trying to get data from cross-domain (i.e from different domain), then you need jsonp request.

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Jun 10, 2012 at 10:33

thecodeparadox

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7 Comments

Bojangles Over a year ago

success: function(data) { ... } is perfectly valid.

Bojangles Over a year ago

Yes, but you said (before your edit) that the arguments are not data, which is incorrect.

thecodeparadox Over a year ago

@JamWaffles I told that for .error(), anyway thanks Sir, for your comment

Bojangles Over a year ago

Ah, so you did, my apologies.

user730936 Over a year ago

#thecodeparadox : thanks for the reply. I have updated the code after making the suggestions, however, i am still getting an error alert "Error: error<>".

|

Bojangles · Accepted Answer · 2012-06-10 10:37:46Z

0

Your data object isn't valid; the key shouldn't be quoted:

data : { puzzle: 'Reset!' }

In addition, SO's syntax highlighting points out that you have missed out a " in your code:

var url_file = myurl";

Should be

var url_file = "myurl;

edited Jun 10, 2012 at 10:37

answered Jun 10, 2012 at 10:31

Bojangles

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1 Comment

user730936 Over a year ago

thanks for the reply. I have updated the data object (edited the original post). But, I am still getting an error alert "Error: error<>".

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