Why do I get "AttributeError: NoneType object has no attribute" using Tkinter? Where did the None value come from?

Question

I've created this simple GUI:

from tkinter import *

root = Tk()

def grabText(event):
    print(entryBox.get())    

entryBox = Entry(root, width=60).grid(row=2, column=1, sticky=W)

grabBtn = Button(root, text="Grab")
grabBtn.grid(row=8, column=1)
grabBtn.bind('<Button-1>', grabText)

root.mainloop()

When I click on the Grab button, an error occurs:

C:\Python> python.exe myFiles\testBed.py
Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Python\lib\lib-tk\Tkinter.py", line 1403, in __call__
    return self.func(*args)
  File "myFiles\testBed.py", line 10, in grabText
    if entryBox.get().strip()=="":
AttributeError: 'NoneType' object has no attribute 'get'

Why is entryBox set to None?

_{See also Why do I get AttributeError: 'NoneType' object has no attribute 'something'? for the general case.}

TODO: make a fully general canonical explaining built-in and library methods that return None, and the design decision behind that (command-query separation). There are many of them, but it is the same problem every time. That covers the other aspect of this problem - stackoverflow.com/questions/8949252 covers understanding the error message. — Karl Knechtel
– Karl Knechtel, Commented Mar 26, 2023 at 5:48

Mike - SMT · Accepted Answer · 2018-03-16 16:17:18Z

148

The grid, pack and place functions of the Entry object and of all other widgets returns None. In python when you do a().b(), the result of the expression is whatever b() returns, therefore Entry(...).grid(...) will return None.

You should split that on to two lines like this:

entryBox = Entry(root, width=60)
entryBox.grid(row=2, column=1, sticky=W)

That way you get your Entry reference stored in entryBox and it's laid out like you expect. This has a bonus side effect of making your layout easier to understand and maintain if you collect all of your grid and/or pack statements in blocks.

edited Mar 16, 2018 at 16:17

Mike - SMT

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answered Jul 9, 2009 at 3:53

Cassie Meharry

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4 Comments

user7420124 Over a year ago

So single line coding is not just syntactical, it also has semantic ramifications which is very unexpected.

Chris Over a year ago

@user7420124, not really. The difference is what you assign to entryBox: in one case it's what Entry() returns, in another it's what grid() returns.

Jonathan Roy Over a year ago

If we want adding a final button like this: tkinter.Button(root, text="Ok", command=lambda: [print(selection), root.destroy()]).pack() pack is require to add it but is not compatible with grid, how to deal that?

chepner Over a year ago

It's only unexpected if you pay no attention to what a method returns. a.b.c simply is not the same as a.b, then a.c.

Aran-Fey · Accepted Answer · 2019-03-25 17:26:36Z

18

Change this line:

entryBox=Entry(root,width=60).grid(row=2, column=1,sticky=W)

into these two lines:

entryBox=Entry(root,width=60)
entryBox.grid(row=2, column=1,sticky=W)

Just as you already correctly do for grabBtn!

edited Mar 25, 2019 at 17:26

Aran-Fey

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answered Jul 9, 2009 at 5:55

Alex Martelli

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Comments

Matiiss · Accepted Answer · 2022-05-26 07:54:17Z

6

Alternative solution for Python3.8+ versions that allows to put all of this in one line using the walrus operator:

(entryBox := Entry(root, width=60)).grid(row=2, column=1, sticky=W)

Now entryBox will refer to the Entry widget and also get packed.

For characters per line management I can suggest something like this:

(var := Button(
    text='fine', command=some_func, width=20, height=15, activebackground='grey'
)).grid(row=0, column=0, columnspan=0, rowspan=0, sticky='news')

But at that point might as well just do this "normally" (as suggested by other answers)

Sources:

edited May 26, 2022 at 7:54

answered Aug 14, 2021 at 10:06

Matiiss

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Comments

7u5h4r · Accepted Answer · 2020-06-23 23:04:14Z

3

For entryBox.get() to access get() method you need Entry object but Entry(root, width=60).grid(row=2, column=1, sticky=W) returns None.

entryBox = Entry(root, width=60) creates a new Entry Object.

Moreover, you won't need entryBox = entryBox.grid(row=2, column=1, sticky=W) as it will rewrite entryBox with None

Just replace entryBox = entryBox.grid(row=2, column=1, sticky=W) with

entryBox = Entry(root, width=60)
entryBox.grid(row=2, column=1, sticky=W)

answered Jun 23, 2020 at 23:04

7u5h4r

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1 Comment

RufusVS Over a year ago

Isn't this just a duplicate of the accepted answer, but 11 years later?

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