How to run command module avail using subprocess?

Question

I want to call module avail and module laod during my python code using subprocess.call which is something like this.

    subprocess.call(['module avail calibre','&','module load calibre'])

But when I run this code it returns:

OSERROR (2, 'No such file or directory')

Any help regarding subprocess??

Enrico · Accepted Answer · 2012-06-15 09:13:20Z

1

If you are trying to run this shell command:

$ module avail calibre & module load calibre

with subprocess try:

subprocess.call(['module','avail','calibre','&','module','load','calibre'])

or:

subprocess.call('module avail calibre & module load calibre',shell=True)

answered Jun 15, 2012 at 9:13

Enrico

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4 Comments

Karan Over a year ago

Got this reult running the second one and first one still gives same OSERROR /bin/sh: module: command not found /bin/sh: calibredrv: command not found /bin/sh: module: command not found

Enrico Over a year ago

This means that your python interpreter can't find the module executable. You can try to use absolute paths, like this: subprocess.call(['/abs/path/to/module','avail','calibre','&','/abs/path/to/module','load','calibre'])

Keith Over a year ago

@Enrico That command line is expected to be interpreted by a shell. It wont work as expected when run without a shell. The & and what follows will just be passed as parameters to "module" command in the first case.

Karan Over a year ago

can it be done in a way that i write a bunch of commands in a scrpit and then pass that script using subprocess....if yes Could you help in giving syntax for that

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