PHP - Get a variables name? Not its content... Its name?

Question

Please see this example:

if (strlen($_SESSION['userDetails']['THISNAME']) == 0)
{
    $_SESSION['userDetails'][''.$THISNAME.'Error'] = "autofocus";
    include "$docRoot/html/forms/reg/user_info.html.php";
    exit();
}

How would i use the name of THISNAME as I have done to create a new variable that appends Error on the name so in this example the output would be THISNAMEError?

Thanks!

You cannot do it, you are approaching problem from wrong angle. — tereško
– tereško, Commented Jun 17, 2012 at 21:11
if you are accessing 'THISNAME' key in your conditional then you know what THISNAME is, so you can assign it to a variable $key = 'THISNAME'; and append error on to it using $key . Error`; — dm03514
– dm03514, Commented Jun 17, 2012 at 21:12
@dm03514 , what he want is this: $foo = 'bar'; echo magic_function($foo); outputs "foo". — tereško
– tereško, Commented Jun 17, 2012 at 21:13
@tereško haha magic_function :) yes I like that... Do you have it? — Craig van Tonder
– Craig van Tonder, Commented Jun 17, 2012 at 21:19
@BlackberryFan , no, you cannot do it. You will have to explain , what is the problem , which you are trying to solve this way. — tereško
– tereško, Commented Jun 17, 2012 at 21:20

Niet the Dark Absol · Accepted Answer · 2012-06-17 21:22:21Z

2

You already know "THISNAME" in order to test its length. Why can't you just put it again where you want it?

As a more general thing, though, you can get the list of keys of an array with array_keys(), or loop through them with foreach($input as $key=>$value).

answered Jun 17, 2012 at 21:22

Niet the Dark Absol

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6 Comments

Craig van Tonder Over a year ago

to answer the first part of your question, because that would involve typing it out twice, and there are alot of fields, that seem to be constantly changing... I've found that appending it manually it making the task cumbersome so I thought, being php there must be a simpler way!? As for the second part... I'll have to think about that, thank you for your input though!

Craig van Tonder Over a year ago

Is there a way to get the names of each field submitted from a form? Like say the form has 4 post fields... a, b, c, d... When you submit the form can you get a output like "a, b, c, d" or is that what array_keys() does?

Niet the Dark Absol Over a year ago

Yup, just use array_keys($_POST). I frequently use that when getting an array of checkboxes.

Craig van Tonder Over a year ago

I have given the answer to tereško as he has provided the code (with the addition of your input) that has solved my problem. Thanks very much!

tereško Over a year ago

@Kolink , thats an extremely bad idea, since you can bypass validation by removing the field.

|

Alex · Accepted Answer · 2012-06-17 21:24:19Z

1

//if(strlen($_SESSION['userDetails'][$THISNAME]) == 0)
//|
//|->if you are checking for $THISNAME,
//   why you then create a new varialbe $THISNAME.'Error' ?

//if(strlen($_SESSION['userDetails']["$THISNAME_Error"]) == 0) {
if( ! isset($_SESSION['userDetails']["$THISNAME_Error"])) {

   $_SESSION['userDetails'][$THISNAME.'_Error'] = "autofocus";
   //or
   $_SESSION['userDetails']["$THISNAME_Error"] = "autofocus";

}

Should work

edited Jun 17, 2012 at 21:24

answered Jun 17, 2012 at 21:10

Alex

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2 Comments

Craig van Tonder Over a year ago

That would get the variable content then append Error to it? so it could be something like w0rldartError? If the variable has the content of w0rldart I need THISNAMEError.

Alex Over a year ago

check my answer's question, it checks to see if (where $THISNAME = 'alex') $_SESSION['userDetails']["alex_Error"]'s length equals to 0.

tereško · Accepted Answer · 2012-06-17 21:26:22Z

0

$required_fields = array( 'name', 'email', 'password', 'password_verification' );
$errors = array();

foreach ( $required_fields as $field )
{
   if ( !isset($_POST[$field]) )
   {
      $errors[$field] = 'not set';
   }
}

if ( count($errors) > 0 )
{
    // there will be errors in thy forms
}

Is this what you are looking for ?

answered Jun 17, 2012 at 21:26

tereško

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2 Comments

Craig van Tonder Over a year ago

See the answer and comments by Kolink

tereško Over a year ago

@BlackberryFan , you cannot replace the $required_fields with just array_keys($_POST) because: it may not contain all the required field names(making possible to bypass validation).

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