PHP regex pattern to format Apache logs

Question

I have got this regex pattern that works with my current apache log format:

preg_match("/^(\S+) (\S+) (\S+) \[([^:]+):(\d+:\d+:\d+) ([^\]]+)\] \"(\S+) (.*?) (\S+)\" (\S+) (\S+) (\".*?\") (\".*?\")$/", $line, $matches); // pattern to format the line

It works with this log:

127.0.0.1 - - [19/Jun/2012:11:38:37 +0200] "GET /some_page HTTP/1.1" 200 8243 "http://example.com/referrer" "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/536.5 (KHTML, like Gecko) Chrome/19.0.1084.56 Safari/536.5"

Now I have changed the apache log format to include the server name, so the new log would be:

127.0.0.1 - - [19/Jun/2012:11:38:37 +0200] **servername.com** "GET /some_page HTTP/1.1" 200 8243 "http://example.com/referrer" "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/536.5 (KHTML, like Gecko) Chrome/19.0.1084.56 Safari/536.5"

The only thing it does it's adding servername.com before the "GET /url...".

Now the regex doesn't work anymore and I don't know what do I have to modify to make it match the new log format.

Bogdan Emil Mariesan · Accepted Answer · 2012-06-19 10:00:22Z

1

Here is your updated regex:

preg_match("/^(\S+) (\S+) (\S+) \[([^:]+):(\d+:\d+:\d+) ([^\]]+)\] [\w.]+ \"(\S+) (.*?) (\S+)\" (\S+) (\S+) (\".*?\") (\".*?\")$/", $line, $matches);

I've added an extra [\w.]+ group that should match your server name.

answered Jun 19, 2012 at 10:00

Bogdan Emil Mariesan

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2 Comments

Alexandru Trandafir Catalin Over a year ago

Hi, it worked! Thanks! I have just added "(" and ")" around it, like this ([\w.]+) to be captured in the matches.

Bogdan Emil Mariesan Over a year ago

oh sure thing, i've forgot about those :)

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