Grep return whole object instead of array

Question

Is there any way i can force grep function of jquery to return new object with reflected new array? For example I have sample JSON and javascript like below.

var myObject = {     "Apps" : [    
    {
        "Name" : "app1",
        "id" : "1",
        "groups" : [
            { "id" : "1", 
              "name" : "test group 1", 
              "desc" : "this is a test group"
             },
            { "id" : "2",
              "name" : "test group 2",
              "desc" : "this is another test group"
             },
              { "id" : "2",
              "name" : "test group 2",
              "desc" : "this is another test group"
             }
        ]              
    }
    ]
   }

 var b,a;
    $.each(myObject.Apps, function() {    
     b = $.grep(this.groups, function(el, i) {
    return el.id.toLowerCase() === "2"                
    });         

   }); 

 alert(JSON.stringify(b));

So Once i run this i will get following text in alert as expected.

[{"id":"2","name":"test group 2","desc":"this is another test group"},{"id":"2","name":"test group 2","desc":"this is another test group"}]

But i want the whole javascript object with this new return array like this. Expected O/p::

 "Apps" : [    
    {
        "Name" : "app1",
        "id" : "1",
        "groups" : [
             { "id" : "2",
              "name" : "test group 2",
              "desc" : "this is another test group"
             },
              { "id" : "2",
              "name" : "test group 2",
              "desc" : "this is another test group"
             }
        ]              
    }
    ]

Any idea would be a great help.

Sure, re-write grep. Can't you just wrap it in the structure you want? — Dave Newton
– Dave Newton, Commented Jun 19, 2012 at 19:26
Copy object, create new object, slice elements out of object, return object. — Ohgodwhy
– Ohgodwhy, Commented Jun 19, 2012 at 19:31
Thanks dave. But i am not sure how can i rewrite grep. Can you give me hint? As i am wondering if i will rewrite grep than i might loose previous functionality. — ravi
– ravi, Commented Jun 19, 2012 at 19:33
@ravi I was being sarcastic--what I'm saying is keep grep the same, and wrap the results in the structure you need. — Dave Newton
– Dave Newton, Commented Jun 19, 2012 at 19:46

charlietfl · Accepted Answer · 2012-06-19 22:04:08Z

4

If understand correctly you want to remove any groups not returned in $.grep from the master object.

Using your $.grep() method add one line in the $.each loop after $.grep

DEMO: http://jsfiddle.net/67Bbg/

var b,a;
$.each(myObject.Apps, function() {    
   b = $.grep(this.groups, function(el, i) {
      return el.id.toLowerCase() === "2"                
   });

  /* replace group with new array from grep */         
   this.groups=b;
 });

EDIT: Abbreviated version

$.each(myObject.Apps, function() {    
    this.groups= $.grep(this.groups, function(el, i) {
      return el.id.toLowerCase() === "2"                
   });
 });

edited Jun 19, 2012 at 22:04

answered Jun 19, 2012 at 21:52

charlietfl

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2 Comments

Fábio Batista Over a year ago

You don't even need a and b, just assign the result of $.grep to this.groups.

charlietfl Over a year ago

@FábioBatista good point, I just was trying to fill in what I think OP was missing

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