I try to output my .php files from the command line and I want to be able to simulate $_SESSION values for this output.
I tried php test.php --define $_SESSION["id"]=1 but it does not set the global variable $_SESSION.
I am obviously not using the command line correctly but I cannot find how I should do.
Any idea to make it work?
Thanks a lot
EDIT: for my example test.php is the following:
<? echo $_SESSION['id'];?>
$ cat setsession.php
<?php
//fixed session:
session_id("fixed");
session_start();
?>
$ cat checksession.php
<?php
if(!isset($_SESSION['counter'])) $_SESSION['counter'] = 0;
$_SESSION['counter']++;
var_dump($_SESSION);
$ php -d auto_prepend_file=setsession.php checksession.php
array(1) {
["counter"]=>
int(1)
}
$ php -d auto_prepend_file=setsession.php checksession.php
array(1) {
["counter"]=>
int(2)
}
$ php -d auto_prepend_file=setsession.php checksession.php
array(1) {
["counter"]=>
int(3)
}
You cannot use sessions on the command line in any meaningful way – the session identifier gets stored in a cookie. The command line doesn't do cookies, so the normal way of sessions doesn't work. Of course, you can use the $_SESSION superglobal during the run of the script. Just don't expect it to persist between different calls of the same script.
$_SESSION variable (as any variable) before running the script. I tried -B and -d options but with no luck.
-d defines ini keys, not variables. php test.php -B '$_SESSION["abc"]="test";' might achieve what you want to be doing.-d however -B '$_SESSION["abc"]="test";' does not seem to be properly setting the variable, neither does -B '$_SESSION=array("abc"=>"test");', not sure why :-/
-B would work equally well as the prepend file I proposed, but (1) we need a session-ident, (2) a session_start destroys a previously set $_SESSION, so, it would be -B 'session_id("fixedorsomething");session_start();$_SESSION["abc"]="test";'. I just prefer to put that stuff in a file so my command line isn't so cluttered (and I don't have to remember every setup, just use the same file next time).
session_start()anywhere in the php file?$_SESSIONand wondered if I could use this global variable as a regular variable. I will try with it.session_start(), the$_SESSIONvariable is set toarray(), which is not the cas if I do not do it (I checked withprint_r. Everything looks like my --define does not do anything (or at least not what I expect)$_SESSIONvariable). Now I am trying to output a static version of my connected page to build a native app with phone gap, that does not know PHP. I want to write a script that exports the logged in version of the page to a standard HTML I use in my phonegap app. Does it make sense? Any easier way to achieve this?