PHP - Echoing a specific string from an array which is result of a function

Question

PHP:

I have made up a function that returns an array. I would like to be able to echo only one part of this array without having to make a variable like this:

$var = meth_0('getPlayerLimit');
echo $var['success'];

Is this possible? I´ve already tested doing what's bellow and it didn´t work.

echo meth_0('getPlayerLimit')['success'];

Thanks for your time :)

no this is not possible, you can use print_r() for verification — Moyed Ansari
– Moyed Ansari, Commented Jun 20, 2012 at 17:31
@MoyedAnsari False, see answers below, it is entirely possible ;) — Mathieu Dumoulin
– Mathieu Dumoulin, Commented Jun 20, 2012 at 17:35
I´ve seen both answers. I understand now. I couldn´t make it work because i´m using PHP Version 5.3.8. I will update :) Thanks — Daniel Silva
– Daniel Silva, Commented Jun 20, 2012 at 17:43

Mathieu Dumoulin · Accepted Answer · 2012-06-20 17:32:11Z

4

It is possible only with php 5.4 and this is called Array Dereferencing, newly added to php.

On another note, you have ways with php 5.3 and less to do this such as:

echo reset(meth_0('getPlayerLimit')); //Success must be first item
echo end(meth_0('getPlayerLimit')); //Success must be last item

or

echo valueOf(meth_0('getPlayerLimit'), 'success');
function valueOf($arr, $idx){ return $arr[$idx]; }

Thats all i can think of!

answered Jun 20, 2012 at 17:32

Mathieu Dumoulin

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Dalen · Accepted Answer · 2012-06-20 17:32:20Z

3

You can do it with PHP 5.4, it is called array dereferencing:

  function get_cars()
  {
    return ["ferrari","lamborghini","maserati","bugatti"];
  }
  echo get_cars()[3];  //bugatti

example taken at http://www.waynemay.com/function-array-dereferencing-in-php-5-4-03052012

answered Jun 20, 2012 at 17:32

Dalen

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