Cannot get value from array

Question

I seem to be having a problem checking if a string exists in my array. There is probably a really obvious answer to my question do forgive me but I'm new to PHP.

Anyway here is my code:

while($row = mysql_fetch_assoc($result))
{
    $result_array[] = $row;
}

if (in_array("496891", $result_array)) 
{
echo "true";
}
else
{
echo "false";
}

The array looks like this:

Array ( [0] => Array ( [ID] => 496891 ) [1] => Array ( [ID] => 1177953 ))

My code always echoes false. Anyone know what I'm doing wrong?

Thanks

in_array only checks the "first" level of a array. You have a multidimensional one. — OptimusCrime
– OptimusCrime, Commented Jun 22, 2012 at 8:01

Cyclonecode · Accepted Answer · 2012-06-22 08:18:20Z

3

You have a nested array and must check against each item like so:

function in_multidimensional_array($val, $array) {
  foreach($array as $key => $value) {
     if (in_array($val, $array[$key])) {
        return true;
     }  
  }
  return false;
}

Now you can check if the value 496891 exists using:

if(in_multidimensional_array('496891', $result_array)) {
   print 'true';
} else {
   print 'false';
}

edited Jun 22, 2012 at 8:18

answered Jun 22, 2012 at 8:01

Cyclonecode

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Comments

OptimusCrime · Accepted Answer · 2012-06-22 08:04:27Z

2

Krister's solution only works if you only have one row in your MySQL-loop. This would check against all the results.

while($row = mysql_fetch_assoc($result))
{
    $result_array[] = $row;
}

$found = false;
foreach ($result_array as $v) {
    if (in_array("496891", $v)) {
        $found = true;
    }
}

if ($found == true)
    echo 'true';
else
    echo 'false';

answered Jun 22, 2012 at 8:04

OptimusCrime

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Comments

Fluffeh · Accepted Answer · 2012-06-22 08:02:08Z

0

You are searching for a string, but your array is holding numeric values. You would need to make sure that you insert it specifically as a string to get it to return true, or each field as a string prior to the search.

answered Jun 22, 2012 at 8:02

Fluffeh

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