Split string into variables PHP

Question

i'm trying to figure out the best way to spilt the following url string:

area-FFFFFF_miles-100_profession-web+developer

basically into the following:

$area = "FFFFFF";
$miles = 100;
$profession = "web developer";

But i've got a brain block and can't really figure out the most efficient way to do it. Any suggestions?

Thanks.

-Edit- I could do with accounting for any missing values, such as:

area-FFFFFF_miles-_profession-web+developer

missing the miles etc.

Andreas Wong · Accepted Answer · 2012-06-29 08:56:32Z

4

$params = explode('_', $input);
foreach($params as $param) {
    $kv = explode('-', $param);
    ${$kv[0]} = str_replace('+', ' ', $kv[1]);
}

This also account for missing values.

edited Jun 29, 2012 at 8:56

answered Jun 29, 2012 at 8:50

Andreas Wong

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1 Comment

peter88uk Over a year ago

Seems to work spot on. Just what I needed. Thanks. There are a few answers that are virtually the same so thanks to everyone :)

dynamic · Accepted Answer · 2012-06-29 08:48:15Z

2

You can use preg_split:

preg_split("/[_-]/",...);

answered Jun 29, 2012 at 8:48

dynamic

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5 Comments

Ben Over a year ago

That splits but it doesn't split in variables, still need to expand

peter88uk Over a year ago

Brilliant. Didn't think of that. Any way I could account for something like this: area-FFFFFF_miles-_profession-web+developer (For example, missing the miles value?

dynamic Over a year ago

I don't understand what you mean. miles isn't missing with your string

peter88uk Over a year ago

The value of miles is missing. Try looking at the 2 edits in the original post.

dynamic Over a year ago

@Ben: ahhh ok now I got you, i didn't understood at a first glance

Niemand · Accepted Answer · 2012-06-29 08:53:28Z

0

Something like this:

$paramsStr = 'area-FFFFFF_miles-100_profession-web+developer';

$parts = explode('_', $paramsStr);
foreach($parts as $part) {
    $pair = explode('-', $part);
    ${$pair[0]} = $pair[1];
}

answered Jun 29, 2012 at 8:53

Niemand

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1 Comment

Niemand Over a year ago

Damn, is this some kind of race? >_< And @SiGanteng, you still have ${$kv[1]}, where you need just $kv[1]

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