to count the occurrence of one string in other string in python

Question

If this is the first string : ABCD

if this is the second string: ABCD is ABCD

I want to count the occurrence of first string in the second string and that too in python. How can I do that?I'm new to python, so facing some problems. Can anyone tell me the solution or provide the code for the same.

Ashwini Chaudhary · Accepted Answer · 2016-07-30 06:29:19Z

3

Use str.count():

>>> str1 = "ABCD"
>>> str2 = "ABCD is ABCD"
>>> str2.count(str1)
2

edited Jul 30, 2016 at 6:29

answered Jul 1, 2012 at 8:50

Ashwini Chaudhary

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6 Comments

POOJA GUPTA Over a year ago

Thanks it worked , The solution was so simple, it skipped from my mind that I can use count :)

Ashwini Chaudhary Over a year ago

@POOJAGUPTA yes it was simple. You can accept the solution if it worked for you.

Raj Over a year ago

If str1 = "AA" and str2 = "AAAA" then the output is 2 if count() is used. But, it is not correct, right ? I think the correct output is 3. Because, 1st substring is index 0 & index 1 together. 2nd substring is index 1 & index 2 together. 3rd substring is index 2 & index 3. So, the correct output is 3, right ? Please clarify.

Ashwini Chaudhary Over a year ago

@RajKumarRampelli Nop, 2 is the correct output in that case as it returns the number of non-overlapping occurrences. To get the overlapping count you can use regex: len(re.findall('(?=AA)', 'AAAA')) == 3.

Raj Over a year ago

The re.findall('(?=AA)', 'AAAA') expression return the list [' ', ' ', ' '] and which is of length 3. When I used regex 'AA' instead of '(?=AA)' then the output is ['AA', 'AA']. My query is why the output doesn't contain substrings 'AA' when regex '(?=AA)' used ? also, what is the use of '?=' ?

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