PHP not triggering an error

Question

I just did a syntax like this

mysql_real_escape_string($var = 'Hello');
print_r($var);

and I got the echo of Hello, so I wondering is that syntax legal in PHP? if not why doesn't PHP trigger an error that is not legal?

yes it is... i actually use it often int templates instead of using a separate declaration block. — prodigitalson
– prodigitalson, Commented Jul 2, 2012 at 13:25
$var='Hello' was successful so you really did mysql_real_string_escape(true); (p.s. its mysql_real_escape_string) — Waygood
– Waygood, Commented Jul 2, 2012 at 13:26

Pekka · Accepted Answer · 2012-07-02 13:32:08Z

3

mysql_real_string_escape($var = 'Hello');

That's legal, although it won't do what you want.

Hello is assigned to $var and then the value is used as an argument to call the function.

However, $var will not be escaped this way! The return value of mysql_real_escape_string() will be lost.

So don't do this. The right way to do it would be

$var = "Hello";
$var_escaped = mysql_real_escape_string($var);

print_r($var_escaped);

answered Jul 2, 2012 at 13:24

Pekka

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3 Comments

But the function mysql_real_string_escape not working at all when I do this.

I think that the function is mysql_real_escape_string() :)

mysql_real_string_escape or mysql_real_escape_string?