How to select a directory and store the location using tkinter in Python

Question

I am creating a GUI with a browse button which I only want to return the path. I've been looking at solutions using code like below.

Tkinter.Button(subframe, text = "Browse", command = self.loadtemplate, width = 10).pack()

   def loadtemplate(self): 
        filename = tkFileDialog.askopenfilename(filetypes = (("Template files", "*.tplate")
                                                             ,("HTML files", "*.html;*.htm")
                                                             ,("All files", "*.*") ))
        if filename: 
            try: 
                self.settings["template"].set(filename)
            except: 
                tkMessageBox.showerror("Open Source File", "Failed to read file \n'%s'"%filename)

However I know Tkinter has a built in askopenfilename which is a super easy one line of code for opening files. Is there some way to modify this to return the directory instead of a file? Is there a smaller option than the larger chunk of code I posted?

mgilson · Accepted Answer · 2019-04-22 13:24:20Z

120

It appears that tkFileDialog.askdirectory should work. documentation

edited Apr 22, 2019 at 13:24

answered Jul 2, 2012 at 14:58

mgilson

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1 Comment

Hofbr Over a year ago

the documentation for the askdirectory only seems to have information around a Python 2.7 version. Is there not a version 3?

Mohammad Usman · Accepted Answer · 2018-03-21 08:39:06Z

45

This code may be helpful for you.

from tkinter import filedialog
from tkinter import *
root = Tk()
root.withdraw()
folder_selected = filedialog.askdirectory()

edited Mar 21, 2018 at 8:39

Mohammad Usman

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answered Mar 21, 2018 at 5:59

Siva Madugula

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1 Comment

Michael S Over a year ago

I've just been researching this for a bit, so I recognize the root.withdraw() as a solution for this question: stackoverflow.com/questions/9319317/… - where they want to know how to keep the root window closed for a command line program.

Mahammadhusain kadiwala · Accepted Answer · 2022-05-31 08:00:48Z

5

Go with this code First, select the directory for creating a new file

import tkinter as tk
from tkinter import filedialog

root = tk.Tk()
root.withdraw()
# file_path = filedialog.askopenfilename()
file_path = filedialog.askdirectory()

new_file = input("Name file\n")
open_file = open(f"{file_path}\%s.py" % new_file, 'w')

in my case

i created (ok.py) file in ppppp directory

path is: PS C:\Users\demo\Desktop\ppppp\ok.py

answered May 31, 2022 at 8:00

Mahammadhusain kadiwala

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