PHP Button Needed to call a function

Question

How do I turn the below code into a button on my page? It works the way its written but I don't like that it's a hyperlink. I would prefer it to be a button.

echo " <form>
<a href='test.php?id=$key&do=unfollow'>unfollow</a>
</form>";

Are you familiar with how buttons interact with PHP?

Ryan B
– Ryan B

2012-07-02 18:29:31 +00:00
Commented Jul 2, 2012 at 18:29 — Ryan B
– Ryan B, Commented Jul 2, 2012 at 18:29
do u want this action in javascript? is it ok for u?

sree
– sree

2012-07-02 18:32:12 +00:00
Commented Jul 2, 2012 at 18:32 — sree
– sree, Commented Jul 2, 2012 at 18:32

mgraph · Accepted Answer · 2012-07-02 18:28:00Z

1

Try:

echo " <form action='test.php' method='GET'>
<input type='hidden' name='id' value='$key'/>
<input type='submit' name='do' value='unfollow'/>
</form>";

answered Jul 2, 2012 at 18:28

mgraph

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1 Comment

Steven Over a year ago

This approach worked for me. Thanks mgraph. Exactly what I was looking for.

Rakesh Shetty · Accepted Answer · 2012-07-02 18:51:02Z

0

First: Your link does not have to be inside a FORM. This is because you don't have user input, and because you are using GET.

Second: Use CSS to style the hyperlink and make it look like a button.

edited Jul 2, 2012 at 18:51

Rakesh Shetty

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answered Jul 2, 2012 at 18:28

Saeverix

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