Execution of java command in Runtime

Question

Process process2 = Runtime.getRuntime().exec(new String[]{"javac","-g:vars","/Users/amol/Documents/Java/a.java"});
Process process3 = Runtime.getRuntime().exec(new String[]{"javap","-l","-c","/Users/amol/Documents/Java/a"});

I tried to run this code but I am facing a strange problem. It compiles correctly (means the first line compiles the program) but the second line gives an error saying that 'a' not found. However when I checked the given directory a.class file was created correctly. How should I correctly run the second line?

I run this code on and it works!!!

Shahryar
– Shahryar

2012-07-04 06:34:42 +00:00
Commented Jul 4, 2012 at 6:34 — Shahryar
– Shahryar, Commented Jul 4, 2012 at 6:34

Jon Skeet · Accepted Answer · 2012-07-04 06:28:36Z

2

javap takes a class name, not a filename. You probably want to execute:

javap -l -c -classpath /Users/amol/Documents/Java a

(Split that into string arguments appropriately, of course.)

Note that this will still fail if a is in a package - or if the class in a.java isn't actually a at all (which is valid for non-public classes). In both of these cases, you'd need to determine the classes involved, probably by building into an empty directory and finding out which files are produced by javac.

answered Jul 4, 2012 at 6:28

Jon Skeet

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1 Comment

Blood Sport Over a year ago

Thanks a lot. It worked after adding the classpath argument..:)

cutebug · Accepted Answer · 2012-07-04 06:29:23Z

1

You may have to specify the classpath argument for javap upto the directory of the class.

Process process3 = Runtime.getRuntime().exec(new String[]{"javap","-l","-c","-classpath  \"/Users/amol/Documents/Java/\"","a"});

answered Jul 4, 2012 at 6:29

cutebug

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