This Javascript code returns 'Undefined' [duplicate]

Question

Possible Duplicate:
Function Arguments Passing and Return

I need a little help with this

 var foo = {
     bar: function () {
         return this.baz;
     },
     baz: 1
 };
 (function () {
     return typeof arguments[0]();
 })(foo.bar);

This snippet when executed returns 'undefined' Can someone please explain why is this so ?

@leppie with google I found this stackoverflow.com/q/8587730/995876 :P How sad that the accepted answer there is incorrect :X — Esailija
– Esailija, Commented Jul 4, 2012 at 8:43
@Esailija: That's not even the one I recall! It was a week or 2 ago. — leppie
– leppie, Commented Jul 4, 2012 at 8:45
@Esailija - Good find! Completely identical. This question should be closed, even if the accepted answer in the duplicate is incorrect. — James Allardice
– James Allardice, Commented Jul 4, 2012 at 8:47
@JamesAllardice the code in the questions is actually from perfection kills quiz, question 6 — Esailija
– Esailija, Commented Jul 4, 2012 at 8:59

Andy Bisson · Accepted Answer · 2012-07-04 08:49:40Z

0

You need to use the right scope for the call. Explicitly setting foo as the scope gives the expected result.

var foo = {
    bar: function () {
        return this.baz;
    },
    baz: 1
};
(function () {
    return arguments[0].call(foo);
})(foo.bar);

answered Jul 4, 2012 at 8:49

Andy Bisson

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