How to display image one by one when taking array?

Question

I am beginner of iphone, I have all images in array but how to display one by one when I execute the array in a loop..

NSArray *images = [[NSArray arrayWithObjects:   
                        [UIImage imageNamed:@"1.png"],
                        [UIImage imageNamed:@"2.png"],
                        [UIImage imageNamed:@"3.png"],
                        [UIImage imageNamed:@"4.png"],
                        nil] retain];  


 int i=0;
    int width = 0;
    int height = 0;
    for ( NSString *imageName in images )
    {
        //NSTimer *timer=[[NSTimer alloc]init];
        UIImage *image = [images objectAtIndex:i];
        //UIImage *image = [UIImage imageNamed:imageName];
        animalphoto = [[UIImageView alloc] initWithImage:image];
        animalphoto.contentMode = UIViewContentModeScaleAspectFit;
        animalphoto.clipsToBounds = YES;



        animalphoto.animationDuration=5.0;
        animalphoto.animationRepeatCount=0;

        animalphoto.frame = CGRectMake( animalphoto.frame.size.width * i++, 0, animalphoto.frame.size.width, animalphoto.frame.size.height);


       width = animalphoto.frame.size.width;
        height = animalphoto.frame.size.height;
        NSLog(@"print:%@",image);
        [animalphoto release];
    }


}

Give any suggestion and sample code which is apply in our code..

Use this method : imgView.animationImages = images;

Dhruv
– Dhruv

2012-07-05 11:13:49 +00:00
Commented Jul 5, 2012 at 11:13 — Dhruv
– Dhruv, Commented Jul 5, 2012 at 11:13

The iOSDev · Accepted Answer · 2012-07-05 11:15:18Z

1

Instead of putting one image just put whole array of images to the imgview.animationImages = images without the for loop

For further reference visit this site.

answered Jul 5, 2012 at 11:15

The iOSDev

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Comments

Saurabh Passolia · Accepted Answer · 2012-07-05 11:15:17Z

0

you need to use UIImageView's object animationImages to set the UIImage array
set animationRepeatCount
set animationDuration
then call [imageView startAnimating]; to start the animation

answered Jul 5, 2012 at 11:15

Saurabh Passolia

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