When I write:
alert(<?php echo "33333";?>);
it works.
If I echo a number, it works too. But if I write
alert(<?php echo "346346gj";?>);
it doesn't work.
Can someone tell me why?
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5 Answers
alert(<?php echo "33333";?>); will output alert(33333);. And it's a correct javascript syntax.
alert(<?php echo "346346gj";?>); will output alert(346346gj);. It's not a correct syntax.
When you want to alert a string in javascript you write alert("346346gj"); or alert('346346gj');
So you must replace alert(<?php echo "346346gj";?>); with one of the following:
alert('<?php echo "346346gj";?>');alert("<?php echo "346346gj";?>");alert('<?php echo '346346gj';?>');alert("<?php echo '346346gj';?>");alert(<?php echo "'346346gj'";?>');alert(<?php echo '"346346gj"';?>');
And there are still different conbinations.
Comments
Make sure you enclose the generated JS in quotes:
alert('<?= $stringVariable ?>');
Comments
I'm not sure if I understood your problem, but
alert(""+number);
Maybe I misunderstood you. If you want to print php values in JavaScript, you should request them via ajax. "Hardcoding" them isn't the way to go.
1 Comment
Alexandre Khoury
If he has already the value in php before generating the Javascript, why should he use Ajax?
Because in javascript, strings need to be in quotes.. so try
alert('<?php echo "33333j";?>');
answered Jul 7, 2012 at 16:12
Gabriele Petrioli
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Comments
To output any kind of PHP value (except resources) directly into JavaScript, use json_encode.
alert(<?php echo json_encode($myvar); ?>);
$myvar can be pretty much anything, and it will always work. I alwyas use json_encode to put a PHP variable into JS.
answered Jul 7, 2012 at 16:23
Niet the Dark Absol
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1 Comment
Alexandre Khoury
Bach Fuc said
why? not how?