Finding Key value from JSON Object in Javascript

Question

I hava a JSON Object in my javascript code that is like :

{"0" : "Jul 09, 2012 05:05 PM", "3" : "Jul 09, 2012 05:08 PM"}

I have decoded this JSON using

var jsonObj = eval('(' + {/literal}{$json}{literal} + ')');

I can access values using

jsonObj[i]

but this gives me an error if i access jsonObj[2] since it is not in my json.

So i wish to have a way to access first part of JSON i.e. the key part. so that i store them in an array in JS and loop through them.

do you want to use jQuery framework? $.parseJSON (json).

Tom
– Tom

2012-07-10 01:06:07 +00:00
Commented Jul 10, 2012 at 1:06 — Tom
– Tom, Commented Jul 10, 2012 at 1:06

vishakvkt · Accepted Answer · 2012-07-10 01:06:10Z

2

eval is evil. Anyway, if you want to loop through the properties ('keys') of your json, you can do

for(key in jsonObj) {
   if(jsonObj.hasOwnProperty(key)) {
     //do something with the values
     // jsonObj[key] 
   }
}

answered Jul 10, 2012 at 1:06

vishakvkt

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3 Comments

CodeMonkey Over a year ago

why is that evil ? Also your thing worked for me. Thanks Vishal

Guffa Over a year ago

@user1290495: It's "evil" because the eval method will execute anything that's in the string, so if it contained script, that would run. A JSON parser on the other hand will only accept a string that actually contains only JSON.

vishakvkt Over a year ago

Exactly what guffa said. Also, the additional requirement is the fact that the 'json string' is expected to be near perfect and will cause problems if there are even small mistakes. So its always better to use an external library like jquery to do this for you (jQuery.parseJSON)

Shawn · Accepted Answer · 2012-07-10 01:03:35Z

0

if (jsonObj.hasOwnProperty('2')) {

}

answered Jul 10, 2012 at 1:03

Shawn

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Comments

BLSully · Accepted Answer · 2012-07-10 01:08:17Z

0

Modern browsers have the "static" method Object.keys(). There is a shim for older browsers. Then you can loop over the returned array of keys, or use .indexOf() or .inArray() if you are using most frameworks.

answered Jul 10, 2012 at 1:08

BLSully

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