http://api.easyjquery.com/ips/ didn't retern value

Question

HTML:

<div class=iplookup>23.25.49.250</div>;
<div class=iplookup>188.2.50.62</div>;

jQuery:

$("div").mouseup(function () {
    IP = $(this).text();
    $.getJSON("http://api.easyjquery.com/ips/", {
        IP: IP
    }, function (data) {
        alert("XXX");
        alert(data.continentName + "\n" + data.countryName + " " + data.cityName);
        $(this).append("=" + data.countryName + "," + data.cityName);

    });

});

What is wrong with this code? Why isn't the alert() shown?

Nik could have a valid point with his answer. But other potential problems could be so much as there is no return data, the data returned isn't valid JSON (might be a string). Other. — chris
– chris, Commented Jul 10, 2012 at 17:36

Community · Accepted Answer · 2017-05-23 12:27:53Z

0

The service is not returning JSONP, which you need for cross domain calls. See here for similar issue.

edited May 23, 2017 at 12:27

CommunityBot

11 silver badge

answered Jul 10, 2012 at 17:34

Nik

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